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Afina-wow [57]
4 years ago
11

Problem Solving | Should your directions to a friend for traveling from one city to another include displacements or distances?

Explain.

Physics
1 answer:
wlad13 [49]4 years ago
3 0
This should include distances.  Displacement is the shortest distance from point A to point B.  Distance is the total length of travel.  For an example I have included a simple map.

Displacement would not be an accurate representation of the driving instructions because it would not tell the total length of travel.  Basically, the driver would be going through buildings if you told them displacement.  Directions would tell them the roads traveled.

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If something is hot, does it contain heat or thermal energy?
zysi [14]
I am absolutely sure that if something is hot,  it contain thermal energy only because <span>if a given body is heated its electrons start to move very fast which means that thermal energy is being produced. Hope everything is clear! Regards!</span>
8 0
3 years ago
Assume that the average mass of each of the approximately 1 billion people in China is 55 kg.Assume that they all gather in one
Harman [31]

Answer: 5.9(10)^{-8} m

Explanation:

The equation to calculate the center of mass C_{M} of a particle system is:

C_{M}=\frac{m_{1}r_{1}+m_{1}r_{1}+...+m_{n}r_{n}}{m_{1}+m_{2}+...+m_{n}}

In this case we can arrange for one dimension, assuming the geometric center of the Earth and the ladder are on a line, and assuming original center of mass located at the Earth's geometric center:

C_{M}=\frac{m_{E}(0 m) + m_{p} r_{E-p}}{m_{E}+m_{p}}

Where:

m_{E}=5.9(10)^{24} kg is the mass of the Earth

m_{p}=55(10)^{9} kg is the mass of 1 billion people

r_{E}=6371000 m is the radius of the Earth

r_{E-p}=6371000 m- 2m=6370998 m is the distance between the center of the Earth and the position of the people (2 m above the Earth's surface)

C_{M}=\frac{m_{p}55(10)^{9} kg (6370998 m)}{5.9(10)^{24} kg+55(10)^{9} kg}

C_{M}=5.9(10)^{-8} m This is the displacement of Earth's center of mass from the original center.

8 0
3 years ago
A model rocket rises with constant acceleration to a height of 4.2 m, at which point its speed is 27.0 m/s. How much time does i
geniusboy [140]

Answers:

a) t=0.311 s

b) a=86.847 m/s^{2}

c) y=1.736 m

d) V=17.369 m/s

Explanation:

For this situation we will use the following equations:

y=y_{o}+V_{o}t+\frac{1}{2}at^{2} (1)  

V=V_{o} + at (2)  

Where:  

y is the <u>height of the model rocket at a given time</u>

y_{o}=0 is the i<u>nitial height </u>of the model rocket

V_{o}=0 is the<u> initial velocity</u> of the model rocket since it started from rest

V is the <u>velocity of the rocket at a given height and time</u>

t is the <u>time</u> it takes to the model rocket to reach a certain height

a is the <u>constant acceleration</u> due gravity and the rocket's thrust

<h2>a) Time it takes for the rocket to reach the height=4.2 m</h2>

The average velocity of a body moving at a constant acceleration is:

V=\frac{V_{1}+V_{2}}{2} (3)

For this rocket is:

V=\frac{27 m/s}{2}=13.5 m/s (4)

Time is determined by:

t=\frac{y}{V} (5)

t=\frac{4.2 m}{13.5 m/s} (6)

Hence:

t=0.311 s (7)

<h2>b) Magnitude of the rocket's acceleration</h2>

Using equation (1), with initial height and velocity equal to zero:

y=\frac{1}{2}at^{2} (8)  

We will use y=4.2 m :

4.2 m=\frac{1}{2}a(0.311)^{2} (9)  

Finding a:

a=86.847 m/s^{2} (10)  

<h2>c) Height of the rocket 0.20 s after launch</h2>

Using again y=\frac{1}{2}at^{2} but for t=0.2 s:

y=\frac{1}{2}(86.847 m/s^{2})(0.2 s)^{2} (11)

y=1.736 m (12)

<h2>d) Speed of the rocket 0.20 s after launch</h2>

We will use equation (2) remembering the rocket startted from rest:

V= at (13)  

V= (86.847 m/s^{2})(0.2 s) (14)  

Finally:

V=17.369 m/s (15)  

5 0
3 years ago
A child pushes a 100 kg refrigerator with a force of 50 N, but the refrigerator does not move. Suppose the coefficient of static
faust18 [17]

Answer:

50 N

Explanation:

Since the refrigerator doesn’t move, that means the force of friction equals the amount of force the child exerts on the fridge. If the friction force were greater than the force by the child, the fridge would start accelerating towards the child. If it were less than the force the child exerted, the fridge would start accelerating away from the child. Therefore, the net force must be 0, in this case, the friction force is equal to the force the child exerted, for it to stay at rest (as Newton’s First Law stated).

I hope this helps! :)

8 0
3 years ago
A baseball is struck home plate and acquires a speed of 60m/s. It rises to a height of 100.0 m above its starting level. Find it
Lady bird [3.3K]

Answer:

40 m/s.

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 60 m/s

Height (h) = 100 m

Acceleration due to gravity (g) = 10 m/s²

Final velocity (v) =?

The velocity at height 100 m can be obtained as follow:

v² = u² – 2gh (since the ball is going against gravity)

v² = 60² – (2 × 10 × 100)

v² = 3600 – 2000

v² = 1600

Take the square root of both side

v = √1600

v = 40 m/s

Thus, velocity at height 100 m is 40 m/s

7 0
3 years ago
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