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2 years ago

10

B. What is the volume of the prism in cm3? Show your reasoning. If you

1 answer:

Anastaziya [24]2 years ago

8 0

Answer:

Step-by-step explanation:

Volume of a rectangular prism is length × height × width

Length=7 1/2

Width= 15 1/2

Height=12

Volume of the prism is therefore:

7 1/2×12×15 1/2= 1395cm3

No of cubes with edge length 1/2 to fit into the prism will be:

Volume of cube is L*W*H

1/2*1/2*1/2= 1/8cm3

Therefore the no of cubes to fit into the Prism will be:

1395/(1/8)= 11160 cubes.

If one was stuck,the number of 1/2 edge length cube to fit into 1cm will be:

1/(1/8)= 8 cubes

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2 years ago

Read 2 more answers

A spinner has equal regions numbered 1 through 20. What is the probability that the spinner will stop on an odd number or a mult

klio [65]

Answer:

<em>Probability that the spinner will stop on an odd number or a multiple of 5 is </em><em>0.6</em>

Step-by-step explanation:

Probability = $\frac{Required outcomes}{Total possible outcomes}$

We are given the equal regions numbered from 1 through 20 which means that our total possible outcomes are 20

<em>Total possible outcomes: 20</em>

<em>Outcomes that spinner will stop on an odd number, n(Odd): 10</em>

1, 3, 5, 7, 9, 11, 13, 15, 17, 19

Probability of spinner stoping on Odd number:

P(Odd) = $\frac{n(Odd)}{Total}$ = $\frac{10}{20}$ = $\frac{1}{2}$ = 0.5

Outcomes that spinner will stop on a multiple of 5, n(5): 4

5, 10, 15, 20

Probability of spinner stoping on multiple of 5:

P(5) = $\frac{n(5)}{Total}$ = $\frac{4}{20}$ = $\frac{1}{5}$ = 0.2

Odd numbers which are a multiple of 5 are: 5 and 15

So,

P(Odd and 5) = $\frac{2}{20}=\frac{1}{10}=0.1$

Thus Probability of spinner stopping at odd number or a multiple of 5 becomes:

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2 years ago

A board of length 7 divided by the quantity x minus 2 end of quantity meters was cut into two pieces. If one piece is 3 divided

bulgar [2K]

Answer:

Length of other board $=\frac{4x+20}{x^{2} -4}$ metres

Step-by-step explanation:

Given: Length of board = $\frac{7}{x-2}$ metres

Length of board was divided into two.

Length of one piece = $\frac{3}{x+2}$ metres

Let $l$ = length of the other board

Length of the other board = Length of board - Length of one piece

So, $l=\frac{7}{x-2}-\frac{3}{x+2}$

$l=\frac{7(x+2)-3(x-2)}{(x-2)(x+2)} \\\\l=\frac{7x+14-3x+6}{x^{2} -4} \\\\l=\frac{4x+20}{x^{2} -4}$

Thus, length of the other board $=\frac{4x+20}{x^{2} -4}$ metres

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2 years ago

Compute: 3 .2. -4 plzz help me

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Answer:

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1 year ago