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Yakvenalex [24]
3 years ago
11

Quadrilateral ABCD is a parallelogram with AB = 3y – 6, BC = 5x – 8, CD = 2y + 4, and AD = 4x –1. Find x.

Mathematics
1 answer:
Furkat [3]3 years ago
6 0
In parallelogram ABCD, opposite sides are congruent, it means 
AB = CD
BC = AD
So, 3y – 6 = <span>2y + 4 ........1
and </span>5x – 8 = <span>4x –1...........2
now we can find the value of x and y from expression 1 and 2, 
</span>3y – 6 = 2y + 4
3y-2y = 4+6
y = 10
5x – 8 = 4x –1
5x-4x = -1+8
x = 7
Thus, the value of x is 7, option A is the correct.

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aliya0001 [1]

Answer: 8x+3x=12x+9

The number is -9.

Step-by-step explanation: Combine like terms.

11x=12x+9

Subtract 12x from the other side. 11x-12x= -1x

-1x+9

Divide by -1 to isolate x.

-1/-1 cancels out.

9/-1= -9

x=-9

Plug in -9 to check your answer if you want to double check.

3 0
3 years ago
What is the inverse of f(x)=3x+6 ?
scZoUnD [109]

Answer:

\boxed{\sf \ \ f^{-1}(x)=\dfrac{x-6}{3} \ \ }

Step-by-step explanation:

hello,

we can write

fof^{-1}(x)=x \ and \ fof^{-1}(x)=f(f^{-1}(x))=3f^{-1}(x)+6 \ so\\3f^{-1}(x)+6=x \ \ subtract \ 6\\3f^{-1}(x)=x-6 \ \ divide \ \ by \ \ 3\\ f^{-1}(x)=\dfrac{x-6}{3}

hope this helps

3 0
3 years ago
Which equation represents the polar form of x² + (y + 4)² = 16?
Paraphin [41]

x^2+y^2=r^2\hspace{5em}x=r\cos(\theta )\hspace{5em}y=r\sin(\theta ) \\\\[-0.35em] ~\dotfill\\\\ x^2+(y+4)^2=16\implies x^2+\stackrel{binomial~expansion}{y^2+8y+16}=16 \\\\\\ \underset{x^2+y^2}{r^2} + 8(~\underset{8y}{r\sin(\theta )}~)=16-16\implies r^2+8r\sin(\theta)=0 \\\\\\ r^2=-8r\sin(\theta )\implies \cfrac{r^2}{r}=-8\sin(\theta )\implies r=-8\sin(\theta )

3 0
2 years ago
What is the solution for the determinant?
Liono4ka [1.6K]
<span>The value of the determinant of a 2x2 matrix is the product of the top-left and bottom-right terms minus the product of the top-right and bottom-left terms.

The value of the determinant of a 2x2 matrix is the product of the top-left and bottom-right terms minus the product of the top-right and bottom-left terms.

= [ (1)(-3)] - [ (7)(0) ]
= -3 - 0
= -3

Therefore, the determinant is -3.

Hope this helps!</span>
4 0
3 years ago
Please help! Question above
frez [133]

Answer:

It's the first one. (m  + n - 1) sqrt p

Step-by-step explanation:

We can combine m sqrt p and n sqrt p, resulting in m + n, and combine - sqrt p to become (m + n - 1)sqrt p

3 0
3 years ago
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