Answer:
The perimeter of Δ ABC is 20 + 2
units ⇒ Last answer
Step-by-step explanation:
The perimeter of any triangle is the sum of the lengths of its three sides
The formula of distance between two points is 
In Δ ABC
∵ A = (3 , 4) , B = (-5 , -2) , C = (5 , -2)
∵ AB = 10 units
∵ AC = 2
- To find its perimeter find the length of BC
∵ 
= -5 and 
= -2
∵ 
= 5 and 
= -2
- By using the formula above
∴ 
∴ 
∴ BC = 10 units
To find the perimeter add the lengths of the three sides
∵ P = AB + BC + AC
∴ P = 10 + 10 + 2
- Add like terms
∴ P = 20 + 2
The perimeter of Δ ABC is 20 + 2 units
Answer:
29Kg
Step-by-step explanation:
P1=2Kg
P2=7Kg
P3=31Kg
P3-P1=29Kg
To find P1, P2 and P3 I started assigning the first prime number, 2, to P1 and tried to assign prime numbers to P2 and P3 so that the sum was 40, increasing them at each step.
I was lucky and I got the result after few steps :-)
Answer:
17x^2+5x-1
Step-by-step explanation:
add or subtract like terms
Answer:
32, 47, x+17, 43
Step-by-step explanation:
just add or subtract by 17
Very easy:
put the 10 and 12 end to end then back off the 7 inches
22-7 = 15
