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Alex777 [14]
3 years ago
9

One family spends $134 on 2 adult tickets and 3 youth tickets at an amusement park. Another family spends $146 on 3 adult ticket

s and 2 youth tickets at the same amusement park. What is the price of a youth ticket?
So this is elimination and I'm starting to get the hang of it; so you basically just find out x(let's just say that youth tickets)?
Mathematics
1 answer:
AnnZ [28]3 years ago
8 0
3x + 2y = $134
2x + 3y = $146

Using elimination to solve for x

9x +6y = 3*134 Multiplying 1st equation by 3

-4x -6y = -2*146 | Multiplying 2nd equation by -2



5x = 3*134 - 2*146

5x = $110

x = $22, the cost of the youth ticket

Put x= 22 Into An Equation Then Solve For y

3(22)+2y= 134
66+ 2y=134
Subtract 66
2y=68
Y= 34

CHECKING Answer ($34 being the cost of the adult ticket) y = (134-3*22)/2

3*$22 + 2*$34 = $66 + $68 = $134
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6 0
2 years ago
Work out the percentage discount offered with the family ticket option
ycow [4]

Answer:

15% discount was offered with the family ticket option.

Step-by-step explanation:

So adult is 55 so 55 x 2=110

45 x 2=90

110+90=200 so 170 ( Family ticket )

170 divide by 200=0.85 x 100=85% 100% - 85%=15%

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2 years ago
What is the answer to this question, 2/5×6/7?
Jobisdone [24]

Answer:

12/35

Step-by-step explanation:


Multiply both numerators and denominators.


2/5 * 6/7


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6 0
2 years ago
PLS HELP! YOU WILL GET A GOOD DEED:*
nasty-shy [4]

Answer:

History test

Step-by-step explanation:

28 divided by 40 is 0.7 which equals 70 percent.

39 divided by 60 is 65 percent .

4 0
2 years ago
Read 2 more answers
The question is below​
Cloud [144]

Answer:

See below.

Step-by-step explanation:

a.

The first figure has 1 square. The second figure has a column of 2 squares added to the left. The third figure has a column of 3 squares added to the left. Each new figure has a column of squares added to the left containing the same number of squares as the number of the figure.

b.

Figure 10 has 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55 squares.

c.

The formula for adding n positive integers starting at 1 is:

1 + 2 + 3 + ... + n = n(n + 1)/2

For figure 55, n = 55.

n(n + 1)/2 = 55(56)/2 = 1540

d.

Let's use the formula set equal to 190 and solve for n. If n is an integer, then we can.

n(n + 1)/2 = 190

n(n + 1) = 380

We know that 380 = 19 * 20, so n = 19.

Answer: yes

e.

Use the formula above,

S = n(n + 1)/2, where S is the sum.

f.

n(n + 1) = 1478

38 * 39 = 1482

37 * 38 = 1406

3 0
3 years ago
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