2 years ago

How to perform aerial math for following: 5.1 x 3.5 X 0.5+9.4

Mathematics

1 answer:

iris [78.8K]2 years ago

4 0

I could be wrong, but I would say it's 18.325

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Prove that: tan20+4sin20 =\sqrt{3}

GenaCL600 [577]

Answer:

the answer is 24

Step-by-step explanation:

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3 years ago

Jerome is going to draw a marble from the bag shown below, replace it, and then draw another marble. What is the probability tha

alexira [117]

Marbles in a bag: 3 green, 4 yellow, 5 blue, 8 pink.

Event A - get a green or yellow marble
Event B - get a pink marble

Events A and B are independent because we draw a marble from a bag with 20 marbles in both cases.
$P(A)= \frac{3+4}{3+4+5+8}= \frac{7}{20} 
\\P(B)= \frac{8}{3+4+5+8}= \frac{8}{20} = \frac{2}{5}$

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3 years ago

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Solve for u:−14u+32=−6.

zubka84 [21]

Answer:u=19/7 or 2.714286 or 2 5/7

Step-by-step explanation:

−14u+32=−6

Step 1: Subtract 32 from both sides.

-14u+32-32=-6-32

-14u=-38

Step 2: Divide both sides by -14.

-14u/-14=-38/-14

U=19/7

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3 years ago

Give letter answer if you give equations rewritten I will give extra points :)

Flauer [41]

Answer:

a) -3x -2y = 12

b) 10x = -15y + 60

c) 6x +9y = 18

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3 years ago

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Question 31 pts Prove the statement is true using mathematical induction: 2n-1 ≤ n! Use the space below to write your answer. To

Sladkaya [172]

Answer:

P(3) is true since 2(3) - 1 = 5 < 3! = 6.

Step-by-step explanation:

Let P(n) be the proposition that 2n-1 ≤ n!. for n ≥ 3

Basis: P(3) is true since 2(3) - 1 = 5 < 3! = 6.

Inductive Step: Assume P(k) holds, i.e., 2k - 1 ≤ k! for an arbitrary integer k ≥ 3. To show that P(k + 1) holds:

2(k+1) - 1 = 2k + 2 - 1

≤ 2 + k! (by the inductive hypothesis)

= (k + 1)! Therefore,2n-1 ≤ n! holds, for every integer n ≥ 3.

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2 years ago