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Law Incorporation [45]
2 years ago
14

Which values are solutions to the inequality square root of x is less than 8? A. 55 B. 8 C. -8 D. 4 E. 65 F. -64

Mathematics
1 answer:
Dima020 [189]2 years ago
4 0

9514 1404 393

Answer:

  A.  55

  B. 8

Step-by-step explanation:

We want ...

  √x < 8

  x < 8² . . . . . square both sides

  x < 64

In order for the inequality to make any sense, we must also have ...

  0 ≤ x

So, the solution space is ...

  0 ≤ x < 64

Only answer choices A (55) and B (8) are in that range.

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Vedmedyk [2.9K]
Check the graph and observe where x = 2.

And check where it cuts across the line of the graph.

If you trace the graph carefully, when x = 2, y = -2

So the value of the function is -2.  

I hope this helps.
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3 years ago
The ratio of boys to girls in a class is 4:5 what fraction of the class is boys and what fraction of the class is girls
ale4655 [162]
First, let's start off with the information we already have. Since the ratio is 4 boys to 5 girls, there has to be a minimum of 9 students (4 being boys and 5 being girls).

9 will be the denominator of both of our fractions since the boys and girls are in the same class.

The fraction of boys in the class is 4/9 (since there are 4 boys to 5 girls in a class of 9, we would write 4 over 9) and the fraction of girls in the class is 5/9.

This is a simplified version of the fractions. If this is a multiple-answer question and 4/9 and 5/9 are not up there, try multiplying the fractions with different numbers and see what fractions will be correct. 

But either way, 4/9 and 5/9 are correct :)

7 0
3 years ago
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Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).
Oduvanchick [21]
For two complex numbers z_1=re^{i\theta}=r(\cos\theta+i\sin\theta) and z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi), the product is

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That is, you multiply the moduli and add the arguments. You have z_1=7e^{i40^\circ} and z_2=6e^{i145^\circ}, so the product is

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3 0
3 years ago
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Please help!
Vlada [557]

Option 3: 2^{\frac{5}{6}} is the right answer

Step-by-step explanation:

Given expression is:

(\sqrt{2})(\sqrt[3]{2} )

In order to simplify the expression we have to convert the radicals in exponents

2^{\frac{1}{2}} . 2^{\frac{1}{3}}

As he base is same, the powers can be added

=2^{\frac{3+2}{6}}\\=2^{\frac{5}{6}}

Hence,

Option 3: 2^{\frac{5}{6}} is the right answer

Keywords: Exponents, radicals

Learn more about exponents at:

  • brainly.com/question/4771355
  • brainly.com/question/4786449

#LearnwithBrainly

6 0
3 years ago
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