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nata0808 [166]
4 years ago
12

How do i solve for this and find the missing one?

Mathematics
1 answer:
kompoz [17]4 years ago
7 0

Answer:

your answer is 65 for the two missing angles

you take 50 and subtract it from 180 to get 130 then divide that by 2 you get 65

Step-by-step explanation:

or you can use the line which also equals 180 in all it has 115 on it so u would subtract 50 from it to get one of the angles then u would add 65 and 50 to get 115 and subtract 115 from 180 to get 65

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GaryK [48]

Answer:

The answers are in the attachment

7 0
2 years ago
Sarah is planning to fence in her backyard garden. One side of the garden is 34 feet long, another side is 30 feet long, and the
Sonbull [250]

Answer: $393

Step-by-step explanation: (34’+ 30’+67’) x $3.00 = 131 x 3.00 = 393

8 0
4 years ago
4x-6 + 2x = 18<br> What’s the answer
solmaris [256]

Answer:

x=4

Step-by-step explanation:

4x-6 + 2x = 18

Combine like terms

6x -6 = 18

Add 6 to each side

6x-6+6 =18+6

6x = 24

Divide each side by 6

6x/6 = 24/6

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6 0
4 years ago
Please help : find x
neonofarm [45]

Answer:

Step-by-step explanation: um

3 0
3 years ago
A tank contains 3,000 L of brine with 15 kg of dissolved salt. Pure water enters the tank at a rate of 30 L/min. The solution is
Shalnov [3]

Answer:

Step-by-step explanation:

Volume of tank is 3000L.

Mass of salt is 15kg

Input rate of water is 30L/min

dV/dt=30L/min

Let y(t) be the amount of salt at any time

Then,

dy/dt = input rate - output rate.

The input rate is zero since only water is added and not salt solution

Now, output rate.

Concentrate on of the salt in the tank at any time (t) is given as

Since it holds initially holds 3000L of brine then the mass to volume rate is y(t)/3000

dy/dt= dV/dt × dM/dV

dy/dt=30×y/3000

dy/dt=y/100

Applying variable separation to solve the ODE

1/y dy=0.01dt

Integrate both side

∫ 1/y dy = ∫ 0.01dt

In(y)= 0.01t + A, .A is constant

Take exponential of both side

y=exp(0.01t+A)

y=exp(0.01t)exp(A)

exp(A) is another constant let say C

y(t)=Cexp(0.01t)

The initial condition given

At t=0 y=15kg

15=Cexp(0)

Therefore, C=15

Then, the solution becomes

y(t) = 15exp(0.01t)

At any time that is the mass.

5 0
3 years ago
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