a) The tangent to
at
has slope

and
at this point. It passes through the origin, so its equation is

It also passes through the point
on the curve, so

By substitution,

b) The normal to
at
has slope

It follows that

c) The tangent line equation is then

F(x) = 22x + 33
g(x) = x² - 44x - 55
(g о f)(88) = (22(88) + 33)² - 44(22(88) + 33) - 55
(g о f)(88) = (1936 + 33)² - 44(1936 + 33) - 55
(g о f)(88) = (1969)² - 44(1969) - 55
(g о f)(88) = 3,876,961 - 86,636 - 55
(g о f)(88) = 2,790,325 - 55
(g о f)(88) = 3,790,270
Answer:
4
Step-by-step explanation:
I assume that is supposed to be x squared. A perfect trinomial is the product of a perfect square, (x times a number) squared. With these trinomials, you can look at them as: ax squared times bx + c. When a is 1, the fastest way to get c to make a perfect square is to divide b by 2. In this case, it's 4/2 = 2. The last step is to square that number. 2 squared = 4.
Answer:
MN = 68
Step-by-step explanation:
LN = 91
LM = 23
Points L, M, and N are collinear, therefore, according to the segment addition postulate, the following can be deduced:
LM + MN = LN
23 + MN = 91 (Substitution)
Subtract 23 from both sides
23 + MN - 23 = 91 - 23
MN = 68