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3 years ago

PLEASE HELP ME WITH GEOMETRY What composition of rigid motions maps STR to MNP?

Mathematics

1 answer:

astra-53 [7]3 years ago

6 0

Answer:

first option

Translate seven left followed by mirror over y = 2

Step-by-step explanation:

You might be interested in

Question 1

Bad White [126]

Answer:

n = -15 and n = 9. n = -15 is not reasonable because you can't have negative boxes or negative units of measurement.

Step-by-step explanation:

8(n + 2)(n + 4) = 1,144

(n + 2)(n + 4) = 143

n^2 + 2n + 4n + 8 = 143

n^2 + 6n - 135 = 0

(n + 15)(n - 9) = 0

n + 15 = 0

n = -15

n - 9 = 0

n = 9

I got two solutions: n = -15 and n = 9. Only one is reasonable because you cannot have a negative number of boxes or negative weight.

Hope this helps!

6 0

4 years ago

We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. (a) Find the probability th

Verizon [17]

Answer:

a) There is a 16.6% probability that doubles were rolled.

b) Given that the roll resulted in a sum of 6 or less, there is a 20% probability that doubles were rolled.

c) There is a 30.55% probability that at least one die is a 1.

Step-by-step explanation:

The probability formula is the number of desired outcomes divided by the number of total outcomes.

(a) Find the probability that doubles were rolled. (i.e. the two outcomes are equal)

There are six desired outcomes: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)

There are 36 total outcomes. So:

$P = \frac{6}{36} = 0.166$

There is a 16.6% probability that doubles were rolled.

(b) Given that the roll resulted in a sum of 6 or less, find the conditional probability that doubles were rolled.

The following rolls result in a sum of 5 or less:

(1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (4,1), (4,2), (5,1)

So, there are 15 total outcomes.

3 of them are doubled: (1,1), (2,2), (3,3). So

$P = \frac{3}{15} = 0.2$

Given that the roll resulted in a sum of 6 or less, there is a 20% probability that doubles were rolled.

(c) Find the probability that at least one die is a 1

The following outcomes have at least one die that is 1:

(1,1), (1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(3,1),(4,1),(5,1),(6,1)

So, there are 11 desired outcomes out of 36.

$P = \frac{11}{36} = 0.3055$

There is a 30.55% probability that at least one die is a 1.

6 0

4 years ago

Plz help me!!!!!!!!!!!!!!!!

Serga [27]

Answer:

Well for number 3 it is the fourth join

And for four is the second option

Step-by-step explanation:

Number three is the fourth choice because all you do is take the two numbers and put the colun there.

And for number four is the second option because you do the same

LET ME KNOW ON HOW YOU DID IN THE COMMENTS!!

6 0

3 years ago

Read 2 more answers

Energy for both renewable and nonrenewable sources originally comes from

Korvikt [17]

Answer:

Step-by-step explanation:

the sun is the primary source

6 0

2 years ago

The explicit rule for the arithmetic sequence shown in the graph is a↓n=9.5+2(n-1)

Virty [35]

Answer:

True.

Step-by-step explanation:

The explicit form for an arithmetic sequence is:

$a_n=a_1+d(n-1)$

where $a_1$ is the first term and $d$ is the common difference.

The common difference here is 2 because the y's are going up by 2 while the x's are going up by 1.

Yes, the common difference is the slope.

So we have d=2.

The first term is 9.5 because that is what happens when x=1.

x is n.

y is $a_n$ .

So the answer is true.

----

You can also verify by plugging in numbers for n and see if you get the outputs mentioned in the pairs given:

Let n=1:

$a_1=9.5+2(1-1)$

$a_1=9.5+2(0)$

$a_1=9.5+0$

$a_1=9.5$

Let n=2:

$a_2=9.5+2(2-1)$

$a_2=9.5+2(1)$

$a_2=9.5+2$

$a_2=11.5$

Let n=3:

$a_3=9.5+2(3-1)$

$a_3=9.5+2(2)$

$a_3=9.5+4$

$a_3=13.5$

Let n=4:

$a_4=9.5+2(4-1)$

$a_4=9.5+2(3)$

$a_4=9.5+6$

$a_4=15.5$

Let n=5:

$a_5=9.5+2(5-1)$

$a_5=9.5+2(4)$

$a_5=9.5+8$

$a_5=17.5$

Let n=6:

$a_6=9.5+2(6-1)$

$a_6=9.5+2(5)$

$a_6=9.5+10$

$a_6=19.5$

We have confirmed that we get all 6 of the mentioned points using the equation they gave.

5 0

3 years ago