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Assoli18 [71]
2 years ago
8

If (a+b)^2=54, and (a-b)^=46, then a^2+b^2=?

Mathematics
1 answer:
erastovalidia [21]2 years ago
4 0

(a+b)^2 =a^2 +b^2 + 2ab = 54~~~.....(i)\\\\(a-b)^2 = a^2 +b^2 -2ab = 46~~~.....(i)\\\\\\(i)+(ii):\\\\(a+b)^2 +(a-b)^2  = 54+46\\\\\implies a^2 +b^2 + 2ab + a^2 +b^2 - 2ab =100\\\\\implies 2a^2 +2b^2 =100\\\\ \\\implies 2(a^2 +b^2) =100\\\\\implies a^2 +b^2 = \dfrac{100}2 = 50

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3 years ago
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3 years ago
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docker41 [41]
<span>3x^2y^2 − 2xy^2 − 8y^2 =
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factoring with leading coefficient:

for ax2+bx+c find two numbers n,m, that m*n = a*c and m+n = b
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3x^2 - 2x - 8
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replace bx with mx + nx and factor by grouping
</span><span>
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answer:
<span>3x^2y^2 − 2xy^2 − 8y^2 = y^2(3x+4)(x-2)</span>

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