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Katyanochek1 [597]
4 years ago
9

The probability of Sandy flipping a coin twice and getting heads both times is 0.250.250, point, 25. The probability of John's s

pinner stopping on the color red is \dfrac14
4
1
​
start fraction, 1, divided by, 4, end fraction.
Which of these events is more likely?
Mathematics
2 answers:
Shkiper50 [21]4 years ago
5 0

Answer:

they are the same.

Step-by-step explanation:

Both have a 1/4 chance

AnnZ [28]4 years ago
5 0

Answer:

THE  are all the same  they all hae 1/4 chance

Step-by-step explanation:

I am pretty sure this will help =)

mark me brainliest =)

Have agreat day :)

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Translate the phrase into an algebraic expression. The product of w and 5
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The algebraic expression for a phrase is: 5w.

Hope this help.

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Find the value of “K” given that one solution of the equation 5x?- kx + 40 = 0 is
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Answer:

Interpreting as: + 40 = 0

Input:

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Result:

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3 years ago
Consider randomly selecting a student at a certain university, and let A denote the event that the selected individual
Stells [14]

Answer:

(a) P( A ∩ B )=0.5 is not possible.

(b) 0.7

(c) 0.3

(d) 0.3

(e) 0.4

Step-by-step explanation:

Given information: The alphabet A and B represents the following events

A : Individual has a Visa credit card.

B: Individual has a MasterCard.

P(A)= 0.6 and P(B)=0.4.

(a)

We need to check whether P( A ∩ B ) can be 0.5 or not.

A\cap B\subset A and A\cap B\subset B

P(A\cap B)\leq P(A) and P(A\cap B)\leq P(B)

P(A\cap B)\leq 0.6 and P(A\cap B)\leq 0.4

From these two inequalities we conclude that

P(A\cap B)\leq 0.4

Therefore, P( A ∩ B )=0.5 is not possible.

(b)

Let P(A\cap B)=0.3

We need to find the probability that student has one of these two types of cards.

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Substitute the given values.

P(A\cup B)=0.6+0.4-0.3=0.7

Therefore the probability that student has one of these two types of cards is 0.7.

(c)

We need to find the probability that the selected student has neither type of card.

P(A'\cup B')=1-P(A\cup B)

P(A'\cup B')=1-0.7=0.3

Therefore the probability that the selected student has neither type of card is 0.3.

(d)

The event that the select student has a visa card, but not a mastercard is defined as

A-B

It can also written as

A\cap B'

The probability of this event is

P(A\cap B')=P(A)-P(A\cap B)

P(A\cap B')=0.6-0.3=0.3

Therefore the probability that the select student has a visa card, but not a mastercard is 0.3.

(e)

We need to find the probability that the selected student has exactly one of the two types of cards.

P(A\cap B')+P(A\cap B')=P(A\cup B)-P(A\cap B)

P(A\cap B')+P(A\cap B')=0.7-0.3

P(A\cap B')+P(A\cap B')=0.4

Therefore the probability that the selected student has exactly one of the two types of cards is 0.4.

8 0
3 years ago
Write an inequality for this situation.<br> You cannot go more than 65 mph on route 18.
Pie

Answer:

65<x

Step-by-step explanation:

x would be your speed.

im not really sure, but i did see a similar question and that kinda helped.

3 0
3 years ago
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