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2 years ago

Think about the ecosystem that you live in.

Chemistry

2 answers:

kherson [118]2 years ago

8 0

Answer:

this is an answer for YOU to answer. this is about YOUR ecosystem

Explanation:

just say what it's like, is it a community? is it populated? explain.

LenaWriter [7]2 years ago

5 0

Answer:

Explanation:

this is an answer for YOU to answer. this is about YOUR ecosystem

just say what it's like, is it a community? is it populated? explain.

You might be interested in

How many grams of hcl is dissolved in 500 ml of a 0.2 m hcl solution?

umka21 [38]

It well be 9025 because it will dissolve in 0.8 hcl soluiton

7 0

3 years ago

Consider the reaction: P(s) + 5/2 Cl2(g)PCl5(g) Write the equilibrium constant for this reaction in terms of the equilibrium con

Pani-rosa [81]

Answer: The equilibrium constant for the overall reaction is $K_a\times K_b$

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios.

a) $P(s)+\frac{3}{2}Cl_2(g)\rightarrow PCl_3(g)$

$K_a=\frac{[PCl_3]}{[Cl_2]^{\frac{3}{2}}}$

b) $PCl_3(g)+Cl_2(g)\rightarrow PCl_5(g)$

$K_b=\frac{[PCl_5]}{[Cl_2]\times [PCl_3]}$

For overall reaction on adding a and b we get c

c) $P(s)+\frac{5}{2}Cl_2(g)\rightarrow PCl_5(g)$

$K_c=\frac{[PCl_5]}{[Cl_2]^\frac{5}{2}}$

$K_c=K_a\times K_b=\frac{[PCl_3]}{[Cl_2]^{\frac{3}{2}}}\times \frac{[PCl_5]}{[Cl_2]\times [PCl_3]}$

The equilibrium constant for the overall reaction is $K_a\times K_b$

4 0

3 years ago

A metal M forms the oxide M2O. When 0.890 grams of M reacts with pure oxygen, 0.956 grams of M2O form. Write the balanced equati

Alla [95]

The molar mass of M is 0.225g/mol and the element M is Hydrogen

If a metal M combines with an oxygen element to form the oxide, $M_2O$ then the chemical reaction will be expressed as:

$4M + O_2 -> 2M_2O\\$

This shows that 4 moles of an unknown element M react with the oxygen element to produce the oxide $M_2O$

Given the following parameters

Mass of M = 0.890 grams

Mass of $M_2O$ = 0.956 grams

Get the molar mass of M:

Molar mass = Mass/number of moles

Molar mass = 0.890/4

Molar mass = 0.225g/mol

Hence the molar mass of M is 0.225g/mol and the element M is Hydrogen

Learn more here: brainly.com/question/6996520

5 0

2 years ago

Read 2 more answers

In the reaction 2CO (g) + O2 (g) 2CO2 (g), how many moles of oxygen gas are needed to react with 24 moles of carbon monoxide

Anuta_ua [19.1K]

12 moles of oxygen gas are needed to react with 24 moles of carbon monoxide.

<u>Explanation:</u>

The molar ratio of carbon monoxide to oxygen 2:1

Which means 2 moles of carbon monoxide is reacting with 1 mole of oxygen.

to produce 2 moles of carbon dioxide.

Therefore, from the molar ratio, we get that 12 moles of oxygen are required to react with 24 moles 0f carbon monoxide.

Molar ratio:

The molar ratio gives the moles of product that are formed from a certain amount of reactant, and also the number of moles of a reactant needed to react with another reactant.

4 0

3 years ago

Calculate the number of sodium ions, perchlorate ions, Cl atoms and O atoms in 17.8 g of sodium perchlorate. Enter your answers

Degger [83]

17.8 g of sodium perchlorate contains 8.73 × 10²² Na⁺ ions, 8.73 × 10²² ClO₄⁻ ions, 8.73 × 10²² Cl atoms and 3.49 × 10²³ O atoms.

First, we will convert 17.8 g of NaClO₄ to moles using its molar mass (122.44 g/mol).

$17.8 g \times \frac{1mol}{122.44g} = 0.145 mol$

Next, we will convert 0.145 moles to molecules of NaClO₄ using Avogadro's number; there are 6.02 × 10²³ molecules in 1 mole of molecules.

$0.145 mol \times \frac{6.02 \times 10^{23}molecules }{mol} = 8.73 \times 10^{22}molecules$

NaClO₄ is a strong electrolyte that dissociates according to the following equation.

NaClO₄ ⇒ Na⁺ + ClO₄⁻

The molar ratio of NaClO₄ to Na⁺ is 1:1. The number of Na⁺ in 8.73 × 10²² molecules of NaClO₄ is:

$8.73 \times 10^{22}moleculeNaClO_4 \times \frac{1 ion Na^{+} }{1moleculeNaClO_4} = 8.73 \times 10^{22}ion Na^{+}$

The molar ratio of NaClO₄ to ClO₄⁻ is 1:1. The number of ClO₄⁻ in 8.73 × 10²² molecules of NaClO₄ is:

$8.73 \times 10^{22}moleculeNaClO_4 \times \frac{1 ion ClO_4^{-} }{1moleculeNaClO_4} = 8.73 \times 10^{22}ion ClO_4^{-}$

The molar ratio of ClO₄⁻ to Cl is 1:1. The number of Cl in 8.73 × 10²² ions of ClO₄⁻ is:

$8.73 \times 10^{22}ion ClO_4^{-} \times \frac{1 atomCl }{1ion ClO_4^{-}} = 8.73 \times 10^{22}atom Cl$

The molar ratio of ClO₄⁻ to O is 1:1. The number of O in 8.73 × 10²² ions of ClO₄⁻ is:

$8.73 \times 10^{22}ion ClO_4^{-} \times \frac{4 atomO }{1ion ClO_4^{-}} = 3.49 \times 10^{23}atom O$

17.8 g of sodium perchlorate contains 8.73 × 10²² Na⁺ ions, 8.73 × 10²² ClO₄⁻ ions, 8.73 × 10²² Cl atoms and 3.49 × 10²³ O atoms.

You can learn more Avogadro's number here: brainly.com/question/13302703

8 0

2 years ago