1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lisov135 [29]
2 years ago
11

Think about the ecosystem that you live in.

Chemistry
2 answers:
kherson [118]2 years ago
8 0

Answer:

this is an answer for YOU to answer. this is about YOUR ecosystem

Explanation:

just say what it's like, is it a community? is it populated? explain.

LenaWriter [7]2 years ago
5 0

Answer:

Explanation:

this is an answer for YOU to answer. this is about YOUR ecosystem

just say what it's like, is it a community? is it populated? explain.

You might be interested in
1. A solution is 40.0% acetic acid (characteristic component of vinegar) by mass. The density of this
jekas [21]

the mass of pure acetic acid in 250 ml of this solution is 100 gm

7 0
3 years ago
Satellite photos of Neptune and Uranus show that both planets have a bluish color. Which gas in their atmospheres gives them thi
Shtirlitz [24]

Answer:

Methane

Explanation:

5 0
3 years ago
What are examples of smaller bodies ​
Inga [223]

comets, astroids oort clouds which surround the kuiper belt

8 0
3 years ago
Consider the fructose-1,6-bisphosphatase reaction. Calculate the free energy change if the ratio of the concentrations of the pr
Lyrx [107]

Answer:

The free energy change for the reaction at 37.0°C is -8.741 kJ.

Explanation:

The free energy of the reaction is given by :

\Delta G=\Delta G^o+RT\ln K

where,

\Delta G^o = standard Gibbs free energy

R = Gas constant = 8.314J/K mol

T = temperature in Kelvins

K = equilibrium constant

We have :

\Delta G^o=-16.7 kJ/mol=-16,700 J/mol

1 kJ = 1000 J

T = 37.0 C = 37 +273.15 K = 310.15 K

Ratio of concentrations of the products to the concentrations of the reactants =K = 21.9

\Delta G=-16,700 J/mol+8.314J/K mol\times 310.15 K \ln[21.9]

=-8,741.22 J = -8.741 kJ

The free energy change for the reaction at 37.0°C is -8.741 kJ.

5 0
3 years ago
3. Calculate the average atomic mass for the sample of atoms shown below.
murzikaleks [220]

Answer:B:63.75

Explanation:(5/8 x 63)+(3/8 x 65)=(0.625 x 63)+(0.375 x 65)=63.75

8 0
4 years ago
Other questions:
  • How many molecules (not moles) of NH3NH3 are produced from 6.09×10−4 gg of H2H2? Express your answer numerically as the number o
    5·2 answers
  • How many milliliters of 3.0M phosphoric acid can be made from 95mL of 5.0M solution?
    9·1 answer
  • A fruit fly is classified as a consumer rather than as a producer because it is unable to
    12·1 answer
  • . Substances that CANNOT be broken down chemically into other substances are _____. mixtures solutions compounds elements
    9·1 answer
  • How do you write 145,000,000 in scientific notation?
    6·1 answer
  • You got it wrong!!!!!!!!
    5·2 answers
  • Drag the tiles to the correct boxes. Not all tiles will be used.
    12·1 answer
  • A chemical equation is shown below.
    13·1 answer
  • In which of the following sets is the symbol of the element, the number of protons, and the number of electrons given correctly?
    10·1 answer
  • Taylor has a mass or 500 grams
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!