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kykrilka [37]
2 years ago
9

Taylor has a mass or 500 grams

Chemistry
1 answer:
aliya0001 [1]2 years ago
8 0

Answer:

What this dose not make sence

Explanation:

Please explaplane

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In the following diagram the counter clockwise torque is?
Alina [70]
80Nm I'm pretty sure this is the answer if I'm wrong I'm sorry but I'm positive it the answer
4 0
3 years ago
. A sample of crude oil has a density of 0.87 g/mL. What volume (in liters) does a 3.6 kg sample of this oil occupy
gayaneshka [121]

Answer:

The volume is 4.13793 L

Explanation:

Density is a quantity that expresses the relationship between the mass and the volume of a body, so it is defined as the quotient between the mass and the volume of a body:

density=\frac{mass}{volume}

Density is a characteristic property of every body or substance.

The most commonly used units of density are \frac{kg}{m^{3} } or \frac{g}{cm^{3} } for solids, and \frac{kg}{L} or \frac{g}{mL} for liquids and gases.

In this case, you know:

  • density= 0.87 \frac{g}{mL}
  • mass= 3.6 kg= 3,600 g (being 1 kg=1,000 g)
  • volume= ?

Replacing:

0.87\frac{g}{mL} =\frac{3,600 g}{volume}

Solving:

volume =\frac{3,600 g}{0.87\frac{g}{mL}}

volume= 4,137.93 mL

Being 1,000 mL=1 L, then volume= 4,137.93 mL= 4.13793 L

<u><em>The volume is 4.13793 L</em></u>

5 0
4 years ago
What makes your pulse? Explain​
Serga [27]
Blood flowing into and out your heart makes your pulse
6 0
2 years ago
Starting with the stock solution of 6.0 M, how many milliliters of 6.0 M sulfuric acid are needed to make 450 mL of 1.2 M soluti
Lina20 [59]

<u>Answer:</u> The volume of stock solution needed is 90 mL

<u>Explanation:</u>

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the stock sulfuric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted sulfuric acid solution

We are given:

M_1=6.0M\\V_1=?mL\\M_2=1.2M\\V_2=450mL

Putting values in above equation, we get:

6.0\times V_1=1.2\times 450\\\\V_1=\frac{1.2\times 450}{6.0}=90mL

Hence, the volume of stock solution needed is 90 mL

6 0
3 years ago
What is amu of 99 % H-1, .2% H-1 and .8% H-3
ankoles [38]

The average atomic mass of your mixture is 1.03 u .

The average atomic mass of H is the weighted average of the atomic masses of its isotopes.  

We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its % abundance).  

Thus,  

0.99    × 1.01 u = 0.998 u

0.002 × 2.01 u = 0.004 u

0.008 × 3.02 u = <u>0.024 u</u>

            TOTAL =  1.03   u

4 0
3 years ago
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