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asambeis [7]
3 years ago
13

X^-9*x^-2 a 1/x^18 b 1/x^11 c x^18 d x^11

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
4 0
Exponent rule : a^-x = 1/a^x

x^-9 * x^-2 = 
1/x^9 * 1/x^2 = (when multiplying exponents with same base, add exponents)
1/x^(9 + 2) =
1/x^11

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Could you solve x. If possible could you be fast with it 2x+3=5x+3–3x
Ber [7]

Answer:

3 = 3 (infinitely many solutions)

Step-by-step explanation:

4 0
3 years ago
What is 4 1/5+3 1/10<br><br> a. 7 2/15<br> b. 7 3/10<br> c. 7 1/5<br> d. 7 1/50
Black_prince [1.1K]
7 1/5th is the anwser but thats easy your just being lazy i think
7 0
3 years ago
Dany has a business selling bracelets for 7.50 each. She only has enough material to make 5 bracelets. If x represents the numbe
ziro4ka [17]

Answer:

The range is [0,37.5]

Step-by-step explanation:

We start by writing the equation that links x and y

From the question;

y = 7.5x

Now, she has enough material to make 5 only

When we talk of range, we are referring to the values on the y-axis

So the lowest y value is 0

and since the highest number of bracelets is 5;

The total cost of the 5 is 7.5(5) = 37.5

So the range is [0,37.5]

6 0
2 years ago
The system shown has the unique solution (2, y, z). Solve the system and select the values that complete the solution. y = 0 y =
madreJ [45]
So we are given a system:
3x-2y+3z=0\\&#10;-3x - 5y - 5z= -21
Substitute x = 2 we get the system:
-2y+3z=-6\\&#10;- 5y - 5z= -15
Multiply the first equation by -5 and the second by 2 we get the system:
10y-15z=30\\&#10;- 10y - 10z= -30
Adding the two equations we get :
-25z=0\text{ then}z=0.
We find the value of y by using any of the other equations like this:
-2y=-6\\y=3.
Final solution:
z=0,y=3
8 0
3 years ago
Read 2 more answers
Using the illustration below, calculate the area of the circle.
Keith_Richards [23]
Find thy radius.

Thy radius is 7.25 (D / 2 = R)

Thy formula for area is A = (pi)r^2

Substitute and Solve

A = (pi)r^2
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   = (pi)(52.5625)
   = 165.04625

Therefore, the area is about 165.
6 0
3 years ago
Read 2 more answers
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