Mike discovered that the pool in his backyard is leaking slowly. The pool holds 16,788 gallons of water, and is leaking at a rat
e of 5
gallons per day. If Mike does not replace the water that has leaked from the pool, how many gallons of water will remain in the
after 164 days?
OA. 16,378 gallons
ОВ. 17,608 gallons
OC. 15,968 gallons
OD.
16,952 gallons
Please help
gallons per day. If Mike does not replace the water that has leaked from the pool, how many gallons of water will remain in the
after 164 days?
OA. 16,378 gallons
ОВ. 17,608 gallons
OC. 15,968 gallons
OD.
16,952 gallons
Please help
2 answers:
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First, you have to find out the values of the length and width.
Let l = length and w = width.
Set up your equation for area: l * w = 80
Set up your equation for perimeter: 2l + 2w = 36
We can use substitution for this problem, so find out the value of l or w. In this case, I will use the first equation to find out the value of l.
(Divide w on both sides) l = 80 / w
Since I know that l = 80 / w, I can substitute it into the second equation.
2l + 2w = 36, and l = 80 / w
= 2 (80/w) + 2w = 36
Simplify the equation.
= 160/w + 2w = 36
Get rid of the w in the denominator by multiplying the entire equation by w.
= ( 160/w + 2w = 36 ) * w
= 160 + = 36w
= 2 ( w - 8 ) ( w - 10 )
The solutions for width (w) is 8 or 10. Then, you can use both 8 and 10 as your length and width, either or is fine. Multiply by 4 for each of those values and you get 8 x 4 = 32 and 10 x 4 = 40. The new perimeter would be 2(32) + 2(40) =
a. 144 cm
Hope this helped you! Let me know if there are any confusions :)