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2 years ago

1.Could each value be an input ofthe function? Be prepared to explain your reasoning. 15 84/1/2 300

Mathematics

1 answer:

denpristay [2]2 years ago

4 0

Answer:

Step-by-step explanation:

A function is a specific type of relation in which each input value has one and only one output value. An input is the independent value, and the output value is the dependent value, as it depends on the value of the input.

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A normal population has mean μ-9 and standard deviation σ-5. Round the answers to fou decimal places. Part 1 What proportion of

Anvisha [2.4K]

Answer:

a) $P(X$

And we can find this probability using the normal standard table or excel:

$P(z$

b) $P(X\frac{5-\mu}{\sigma})=P(Z>\frac{5-9}{5})=P(z>-0.8)$

And we can find this probability using the complement rule and the normal standard table or excel and we got:

$P(z>-0.8)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(9,5)$

Where $\mu=9$ and $\sigma=5$

Part a

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And we can find this probability using the normal standard table or excel:

$P(z$

Part b

We are interested on this probability

$P(X>5)$

If we apply the z score formula to our probability we got this:

$P(X\frac{5-\mu}{\sigma})=P(Z>\frac{5-9}{5})=P(z>-0.8)$

And we can find this probability using the complement rule and the normal standard table or excel and we got:

$P(z>-0.8)=1-P(z$

7 0

3 years ago

William wants to keep his debt-to-income ratio at the recommended 15% orlower William's house payment is

3241004551 [841]

9514 1404 393

Answer:

about $171,400

Step-by-step explanation:

William's total monthly debt is ...

$1012.84 +579.13 +250 +300 = 2141.97

On an annual basis, this is ...

12 × $2141.97 = $25,703.64

This will be 15% of (25703.64/0.15) = $171,357.60.

William's new annual salary should be about $171,400 to keep his debt ratio at the recommended 15%.

_____

<em>Additional comment</em>

A debt ratio of 15% is a pretty aggressive target. Most mortgage lenders like to see the "front end" ratio (housing expense) less than 28%, and the "back end" ratio (all debt) less than 36%.

4 0

3 years ago

100 points and brainliest

ololo11 [35]

Answer:

you only gave 50 points but thanks haha

Step-by-step explanation:

3 0

3 years ago

Help!! BRAINLIEST TOO!

natulia [17]

Answer:

36.5 inches

Step-by-step explanation:

Given

See attachment for the given data

Required

Which length is closest to 4.2lb

The given data is a linear dataset.

So, we start by calculating the slope (m)

$m =\frac{y_2 - y_1}{x_2 - x_1}$

Pick any two corresponding points from the table

So, we have:

$(x_1,y_1) = (8,1.21)$

$(x_2,y_2) = (12,1.63)$

So:

$m =\frac{y_2 - y_1}{x_2 - x_1}$

$m =\frac{1.63 - 1.21}{12 - 8}$

$m =\frac{0.42}{4}$

$m =0.105$

The linear equation is then calculated using:

$y = m(x - x_1) + y_1$

This gives:

$y = 0.105 * (x - 8) + 1.21$

Open bracket

$y = 0.105x - 0.84 + 1.21$

$y = 0.105x + 0.37$

To get the length closest to 4.2lb,

we set $y = 4.2$

Then solve for x

So, we have:

$y = 0.105x + 0.37$

$4.2 = 0.105x + 0.37$

Collect like terms

$0.105x= 4.2 - 0.37$

$0.105x= 3.83$

Solve for x

$x= 3.83/0.105$

$x\approx 36.5$

4 0

3 years ago

The U.S. Bureau of Labor Statistics reports that 11.3% of U.S. workers belong to unions (BLS website, January 2014). Suppose a s

vitfil [10]

Answer:

There is not enough evidence to support the claim that union membership increased.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 400

p = 11.3% = 0.113

Alpha, α = 0.05

Number of women belonging to union , x = 52

First, we design the null and the alternate hypothesis

$H_{0}: p = 0.113\\H_A: p > 0.113$

The null hypothesis sates that 11.3% of U.S. workers belong to union and the alternate hypothesis states that there is a increase in union membership.

Formula:

$\hat{p} = \dfrac{x}{n} = \dfrac{52}{400} = 0.13$

$z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Putting the values, we get,

$z = \displaystyle\frac{0.13-0.113}{\sqrt{\frac{0.113(1-0.113)}{400}}} = 1.073$

now, we calculate the p-value from the table.

P-value = 0.141636

Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.

Thus, there is not enough evidence to support the claim that union membership increased.

5 0

3 years ago