Pentagon PQRST and its reflection, pentagon P'Q'R'S'T', are shown in the coordinate plane below:

2 answers:

7 0

Yes, the answer is A. x=0. Another way to say "reflect across the y-axis" is to say "reflect across the line x=0" since the line created by graphing x=0 is the same as the y-axis. An image that is a reflection across the y-axis, or across the line x=0, will have opposite x-coordinates from the pre-image but identical y-coordinates. In other words, the x value points just changed signs from negative to positive values since it went through the rule (x, y) → (−x, y).

Ad libitum [116K]2 years ago

4 0

I have graphed the given coordinates of both pentagons. The reflection was across the y-axis where coordinates of Pentagon PQRST (-x,y) resulted to Pentagon P'Q'R'S'T' (x,y). The line of reflection between the pentagons was x = 0. Line of reflection is the midway between the pre-image and its reflection.

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A ball is thrown upward with an initial velocity of 60 mph. it is thrown from a height of 5 feet. what is the maximum height it

natima [27]

Answer:

h = 61.25 m

Step-by-step explanation:

It is given that,

The initial velocity of the ball, v = 60 m/s

It is thrown from a height of 5 feet, $h_o=5\ ft$

We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

$h=-16t^2+vt+h_0$

Putting all the values,

$h=-16t^2+60t+5$ .....(1)

For maximum height, put

$\dfrac{dh}{dt}=0\\\\\dfrac{-16t^2+60t+5}{dt}=0\\\\-32t+60=0\\\\t=\dfrac{-60}{-32}\\\\t=1.875\ s$

Put t = 1.875 in equation (1)

$h=-16(1.875)^2+60(1.875)+5\\\\h=61.25\ m$

So, the maximum height reached by the ball is 61.25 m.

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3 years ago

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BaLLatris [955]

Answer:

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Step-by-step explanation:

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2 years ago

Negative5 to the negative2 power is what? How do you figure out a negative power?

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Darya [45]

Answer:

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