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Assoli18 [71]
2 years ago
5

Helpppppppppppppppppppppppppppppppppppppppppppp

Mathematics
1 answer:
ahrayia [7]2 years ago
8 0

Answer:

I think it should be 24x^{2}

Step-by-step explanation:

When the question said area of the cube, I think it was supposed to be surface area, which would 6a^{2} where a is the length of one edge. Given that the length of one edge is 2x, we would plug in 2x to the equation to get6*(2x)^{2} which would become 24x^{2}.

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You need to subtract the bonus points form the final score: 91-4=87
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To avoid an additional charge, the sum of the length, 1, width, w, and depth, d, of a piece of luggage to be checked on a
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The answer is B. l+w+d cannot be more than 61 inches so that sum must be less than 61 inches
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Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
3 years ago
Please help! Will mark brainliest! 20 points!
notsponge [240]

8      3

    -

9      4


Get common denominators.

8(4)      3 (9)

        -

9(4)      4 (9)

=

32      27

      -

36      36

=

5/36

5 0
3 years ago
Help pleaseee :)!!!!!!!!!
harkovskaia [24]

Answer:

5x/x+3

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask!

3 0
3 years ago
Read 2 more answers
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