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andrezito [222]
3 years ago
15

Find an equation of the line passing through the points (5, 21) and (-5, -29)

Mathematics
1 answer:
gogolik [260]3 years ago
4 0
Trata 5-29+-5=21 porque ya as tenido este
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Maya is taking her friends to a concert. Each ticket costs $25, and souvenir T-shirts are $12 each. There is a $4 service fee fo
evablogger [386]

Answer:

25x+12y+4 \leq 130

Step-by-step explanation:

Here, x represents the number of tickets and y represents the number of T-shirts.

As per the statement:

Each ticket costs $25,  and souvenir T-shirts are $12 each

⇒Total cost of ticket = 25x and Total cost for T-shirt = 12y

It is also given that there is a $4 service fee for the entire purchase.

25x+12y+4

Since, she has $130

⇒25x+12y+4 \leq 130

Therefore, an inequality could you use to answer the problem is, 25x+12y+4 \leq 130

8 0
3 years ago
According to Greg, perfect cherry pies have a ratio of 240 cherries to 3 pies. How many cherries does Greg need to make 9 perfec
vfiekz [6]
Simple, 3 goes in to 9, 3 times.  That would mean that to find the number of cherries, multiply 240 by 3.  Greg needs 720 cherries for 9 perfect cherry pies.
6 0
4 years ago
Read 2 more answers
Write in full text, no files plz.
slava [35]

Answer:

108 student tickets, and 176 adult tickets were sold.

I hope I helped, and thanks for the points!

Step-by-step explanation:

7 0
3 years ago
Please help me with these. These are so hard.<br><br>​
LuckyWell [14K]

\bf \textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) ~\hfill a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \boxed{a^6+b^6}\implies a^{2\cdot 3}+b^{2\cdot 3}\implies (a^2)^3+(b^2)^3 \\[2em] [a^2+b^2] [(a^2)^2-a^2b^2+(b^2)^2]\implies \boxed{(a^2+b^2)(a^4-a^2b^2+b^4)}

about the second one... well, is a "fait accompli" that using the pythagorean theorem, if x = 8 and y = 5, the hypotenuse must be √(8² + 5²) = √(89), which is neither of those choices.

5, 8, 13 are no dice, namely 5² + 8² ≠ 13

25, 64, 17 is are no dice too, because 25² + 17² ≠ 64²

however, 5,12 and 13 are indeed a pythagorean triple

also is 39, 80, 89.

when looking for a pythagorean triple, recall that c² = a² + b².

so the longest leg is the sum of the square of the small ones.

so what you'd do is, check the small legs, square them, add them up, if they're indeed a pythagorean triple, they "must" add up to the longest leg.

4 0
3 years ago
6895 round to nearest thousand​
garik1379 [7]

Answer:

7000

Step-by-step explanation:

8 0
3 years ago
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