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Kamila [148]
3 years ago
11

Savannah was paid $87 for 12 hours of babysitting and $65.25 for 9 hours. What is the constant of proportionality that describes

this relationship? A) 0.14 B) 7.25 C) 12.5 D) 65
Mathematics
2 answers:
laila [671]3 years ago
8 0
7.25 per hour(NOT GUARENTEED)
ycow [4]3 years ago
4 0
Answer is B) 7.25

87/12 = 7.25
65.25/9 = 7.25
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Find the slope of the line.
lawyer [7]

Answer:

C

Step-by-step explanation:

Well You can tell right away its a positive line since its rising from left to right so the answer has to be positive

If the slope were to be 4 the line would be a Little more titleted becuasea slope of 4 is going up 4 and going tot he right 1.

ANd you can’t heck from any given point and just try all the positivw possibilties.

Or you can just use rise over run, start form a point, rise which means go up until you reach the second layer of the line and just run (go To The right) until you hit a point.

You’ll get 1/4

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What is the volume of the cylinder diameter of 13 and height of 11
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Explanation: google
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What is the value of z?<br><br> Enter your answer in the box.
Georgia [21]

Answer:

23

Step-by-step explanation:

Because the angles of a triangle always add up to 180°, you can set up an equation like this.

62+95+z=180

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4 0
2 years ago
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Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest
11Alexandr11 [23.1K]

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4 0
3 years ago
Solve for XX. Assume XX is a 2×22×2 matrix and II denotes the 2×22×2 identity matrix. Do not use decimal numbers in your answer.
sveticcg [70]

The question is incomplete. The complete question is as follows:

Solve for X. Assume X is a 2x2 matrix and I denotes the 2x2 identity matrix. Do not use decimal numbers in your answer. If there are fractions, leave them unevaluated.

\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =<em>I</em>.

First, we have to identify the matrix <em>I. </em>As it was said, the matrix is the identiy matrix, which means

<em>I</em> = \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

So, \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Isolating the X, we have

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right] -  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Resolving:

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{ccc}2-1&8-0\\-6-0&-9-1\end{array}\right]

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]=\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, we have a problem similar to A.X=B. To solve it and because we don't divide matrices, we do X=A⁻¹·B. In this case,

X=\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]⁻¹·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, a matrix with index -1 is called Inverse Matrix and is calculated as: A . A⁻¹ = I.

So,

\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]·\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]=\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

9a - 3b = 1

7a - 6b = 0

9c - 3d = 0

7c - 6d = 1

Resolving these equations, we have a=\frac{2}{11}; b=\frac{7}{33}; c=\frac{-1}{11} and d=\frac{-3}{11}. Substituting:

X= \left[\begin{array}{ccc}\frac{2}{11} &\frac{-1}{11} \\\frac{7}{33}&\frac{-3}{11}  \end{array}\right]·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Multiplying the matrices, we have

X=\left[\begin{array}{ccc}\frac{8}{11} &\frac{26}{11} \\\frac{39}{11}&\frac{198}{11}  \end{array}\right]

6 0
3 years ago
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