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Lostsunrise [7]
3 years ago
9

Each of the four sides of a swimming pool measures 9 meters. The pool is 5 meters deep. How much water will be needed to fill it

completely? A. 45 cubic meters B. 81 cubic meters C. 225 cubic meters D. 405 cubic meters Reset Next
Mathematics
2 answers:
iragen [17]3 years ago
5 0

The volume of the rectangular prism is equal to length times width times height. Since length and width are equal, the formula includes the squaring of the length. after substitution, the formula is 9^2 * 5 equal to 405 m^3. 

So the answer is D. 405 cubic meters

nikdorinn [45]3 years ago
4 0

Answer: 5 meters

Step-by-step explanation:

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Find number of sides of a regular polygon if each of its exterior angle is 36.​
irinina [24]

Answer:

10 sides,that is, a decagon or 10gon

Step-by-step explanation:

If the exterior angle is 36° then numbers of sides=

36 = \frac{360}{n}

Therefore

n=360°÷36°=10

4 0
3 years ago
Read 2 more answers
Determine whether each expression is equivalent to 49^2t – 0.5.
vampirchik [111]

Answer:

None of the expression are equivalent to 49^{(2t - 0.5)}

Step-by-step explanation:

Given

49^{(2t - 0.5)}

Required

Find its equivalents

We start by expanding the given expression

49^{(2t - 0.5)}

Expand 49

(7^2)^{(2t - 0.5)}

7^2^{(2t - 0.5)}

Using laws of indices: (a^m)^n = a^{mn}

7^{(2*2t - 2*0.5)}

7^{(4t - 1)}

This implies that; each of the following options A,B and C must be equivalent to 49^{(2t - 0.5)} or alternatively, 7^{(4t - 1)}

A. \frac{7^{2t}}{49^{0.5}}

Using law of indices which states;

a^{mn} = (a^m)^n

Applying this law to the numerator; we have

\frac{(7^{2})^{t}}{49^{0.5}}

Expand expression in bracket

\frac{(7 * 7)^{t}}{49^{0.5}}

\frac{49^{t}}{49^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{49^{t}}{49^{0.5}} becomes

49^{t-0.5}}

This is not equivalent to 49^{(2t - 0.5)}

B. \frac{49^{2t}}{7^{0.5}}

Expand numerator

\frac{(7*7)^{2t}}{7^{0.5}}

\frac{(7^2)^{2t}}{7^{0.5}}

Using law of indices which states;

(a^m)^n = a^{mn}

Applying this law to the numerator; we have

\frac{7^{2*2t}}{7^{0.5}}

\frac{7^{4t}}{7^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{7^{4t}}{7^{0.5}} = 7^{4t - 0.5}

This is also not equivalent to 49^{(2t - 0.5)}

C. 7^{2t}\ *\ 49^{0.5}

7^{2t}\ *\ (7^2)^{0.5}

7^{2t}\ *\ 7^{2*0.5}

7^{2t}\ *\ 7^{1}

Using law of indices which states;

a^m*a^n = a^{m+n}

7^{2t+ 1}

This is also not equivalent to 49^{(2t - 0.5)}

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The answer is

X =3

because they both equal the amounts given
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120-2x=30, what’s x?
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Step-by-step explanation:

-2x=30-120

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Where does the oxygen that is used during cellular respiration in animals
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Answer:

A. Air that is breathed in :)

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