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icang [17]
2 years ago
6

Aleesia has a box of 52 muffins. She wants to put out plates that each have the same number of muffins. What is one possible way

Aleesia could put an equal number of muffins on each plate so there are no muffins left over?
Group of answer choices

9 muffins could go on each plate.

13 muffins could go on each plate.

14 muffins could go on each plate.

17 muffins could go on each plate.
Mathematics
1 answer:
Dmitriy789 [7]2 years ago
7 0
13,because it’s the single number that divides with 52
52:13=4
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14. A sphere is inscribed in a cube with an edge of 10. What is the shortest possible distance from one of the vertices of the c
DedPeter [7]

Answer:

5(√3 - 1)

Step-by-step explanation:

Edge of cube = 10

If the sphere is inscribed in a cube, the edges of the cube is equal to the diameter of the sphere.

Diameter = 10

We will then find the diagonal of the cube.

Diagonal = √10^2 + 10^2 + 10^2

= √300

= 10√3

Let X be the distance between the vertex of the cube and the surface of the sphere

X = (diagonal - diameter) /2

X = (10√3 - 10)/2

X = (10(√3 - 1))/2

X = 5(√3 - 1)

8 0
3 years ago
a standard six sided die. Janice rolled either a 2 or a 5 on the last 6 rolls of the die. What is the probability of Janice roll
Igoryamba

We have that   the probability of Janice rolling a 2 or 5 on her 7th toss of the dice is

\frac{1}{3}^7.

From the question we are told that

Janice rolled either a 2 or a 5 on the last 6 rolls of the die

Janice rolling a 2 or 5 on her 7th toss of the dice

P(2/ 5)=1/6+1/6\\\\P(2/ 5)=2/6\\\\P(2/ 5)=1/3.

Where

P(2/5 ) =(1/3)^6.

Janice roll the standard die 7th time the probability of getting 2 or 5 is

P(2/5 ) =\frac{1}{3}^7.

For more information on this visit

brainly.com/question/11234923?referrer=searchResults

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