The answer would be 1.6. The way you do this problem is you square the hypotenuse(in this case 11.56), then subtract the squared version on the side you do have (in this case 9). Then when you subrtact the two, find the square root of the difference (which would be 1.6 in this case).
The age of Blain is 23 years old
<h3><u>Solution:</u></h3>
Let the age of Blain be "a" and age of Jillian be "b"
Given that Blain is two years older than three times Jillians age
So we can frame a equation as:
age of blain = 2 + 3(age of Jillian)
a = 2 + 3b ----- eqn 1
Also given that Jillian is also 16 years younger than Blain
Age of Jillain = Age of Blain - 16
b = a - 16 ---- eqn 2
Substitute eqn 2 in eqn 1
a = 2 + 3(a - 16)
a = 2 + 3a - 48
a - 3a = -46
-2a = -46
a = 23
Thus the age of Blain is 23 years old
Answer:
the answer is 1,078
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>Given</u>
a)
- DC /AB = 3/2 ⇒
- DC = 3/2AB = 3/2p
b)
- BC = AD + (DC - AB)
- BC = q + (3/2p - p) = q + 1/2p
Step-by-step explanation:
I am sorry but please give detailed question
