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2 years ago

Add or subtract. use the least common multiple as the denominator what is 5/8-5/25

Mathematics

2 answers:

Vinvika [58]2 years ago

8 0

Answer:

17/40

Step-by-step explanation:

First let's find the least common denominator. The denominators are 8 and 25 so we need to find the least common multiple of 8 and 25.

8=2*2*2

25=5*5

Since they share no common factors the least common multiple of 8 and 25 is 8*25 which is 200.

Now we convert the fractions:

5/8*25/25=125/200

5/25*8/8=40/200

Then we subtract:

125/200-40/200=85/200

Now we simplify it:

17/40

Nat2105 [25]2 years ago

6 0

Answer:
17/40
Step-by-step explanation:

First, we need to find the common denominator of 5/8 and 5/25, which is 200.

5 x 25/ 8 x 25 - 5 x 8 / 25 x 8
= 125/200 - 40/200

Next, subtract both fractions:

85/200 is our difference.

Let's simplify, divide both sides of the fraction by 5:

85 / 5 and 200 / 5
= 17/40

17/40 is your simplified answer.

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Phoenix [80]

Answer:

Step-by-step explanation:

x- intercept = 2 .So, Coordinate(2 , 0)

y-intercept = 8 . So, Coordinate (0, 8)

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Slope y-intercept form: y = mx + b {Here, b is y-intercept}

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2 years ago

Consider the first three terms of the arithmetic sequence: 7, 15, 23,... Determine d, the common difference.

ValentinkaMS [17]

Answer:

I think 47 and 55

Explanation:

I think that each number is the previous one plus 8;

7+8=15

15+8=23

23+8=31

31+8=39

So, next will be:

39+8=47

47+8=55

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2 years ago

The following data set represents the age of

Julli [10]

$\huge\text{Hey there!}$

$\huge\textsf{Breaking the meaning down in simpler terms}$
$\huge\textbf{Median:}\\\large\text{is understood to be \bf the number in the center (also known as}\\\large\textbf{the middle number)}$

$\huge\textbf{Mean:}\\\large\text{is understood to be the \bf total.}$

$\huge\textsf{Formulas for each term}$

$\huge\text{Median:}\\\large\textsf{To find the median you have to put each of your numbers in your data}\\\large\textsf{set from LEAST (smallest) to GREATEST (biggest). }$

$\huge\text{Mean:}\\\mathsf{\dfrac{sum\ of\ all\ terms}{number\ of\ terms}= mean}$

$\huge\textbf{SOLVING FOR THE QUESTION}$

$\huge\textsf{Median:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textbf{Conversion: }\large\text{27, 33, 38, 41, 42, 52, 64, 68, 72}\\\\\large\textsf{Make sure it is even between both sides of the data plot.}\\\\\large\text{It seems to even on BOTH sides of \boxed{\textsf{14}} so it could possibly be your}\\\large\text{median.}$

$\huge\textsf{Mean:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textsf{Your equation: }\mathsf{\dfrac{27 + 52 + 64 + 41 + 33 + 38 + 42 + 60 +72 + 68}{10}}\\\\\mathsf{\dfrac{79 + 64 + 41 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{143 + 41 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{184 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{217 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{255 + 42 + 60 + 72 + 68}{10}}$

$\mathsf{\dfrac{297 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{357 + 72 + 68}{10}}\\\\\mathsf{\dfrac{429 + 68}{10}}\\\\\mathsf{\dfrac{497}{10}}\\\\\mathsf{\approx 49.70}\\\\\large\text{From the looks of it \boxed{\rm{\dfrac{497}{10}}}\ or \boxed{\text{49.70}} could possibly be your mean.}$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

<h3>
~ $\frak{Amphitrite1040:)}$ </h3>

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2 years ago

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Vikentia [17]

Hello there, and thank you for asking your question here on brainly.

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netineya [11]

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