Help see if i got this right please

To estimate the sum or sum or difference. Estimate: Difference:

Artemon [7]

Answer:

to estimate the sum you round to the closest number like 38 is closest to 40 so you just say you total is $40.00

difference is when say you have 30 dollars and you spend 10 the difference is 10 dollars

3 0

3 years ago

ed fills his sports bottle with 1.2 liters of water after his bike ride he drinks 200 millimeters of water how much water is lef

Iteru [2.4K]

1,2 liters of water = 1.200 millimeters so if he drinks 200 millimeters he has 1,000 millimeters left or 1 liter of water left

6 0

3 years ago

Review the bar graph below:

Scrat [10]

Answer:

B. 12.5%

Step-by-step explanation:

Add all the hours together to get 20. We make the assumption that 20 is 100% since it is our output value. We next represent the value we seek with x. From step 1, it follows that 100%=20. In the same vein, x%=2.5.This gives us a pair of simple equations:

100%=20(1)

x%=2.5(2)

By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS (left hand side) of both equations have the same unit (%); we have

$\frac{100}{x}$ = $\frac{20}{2.5}$

Taking the inverse (or reciprocal) of both sides gives us this:

$\frac{x}{100} =\frac{2.5}{20}$

>> x=12.5\%

Therefore, 2.5 is 12.5% of 20.

5 0

3 years ago

The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.

tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that perpendicular lines have negative reciprocal slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

$\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}$

so, it passes through the midpoint of AB,

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)$

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}$

4 0

3 years ago

What is the image of point (4,3) if the rotation is -270

Gre4nikov [31]

Were is the image so i can help you

6 0

3 years ago