Answer:
Local minimum at x = 0.
Step-by-step explanation:
Local minimums occur when g'(x) = 0 and g"(x) > 0.
Local maximums occur when g'(x) = 0 and g"(x) < 0.
Set g'(x) equal to 0 and solve:
0 = 2x (x − 1)² (x + 1)²
x = 0, 1, or -1
Evaluate g"(x) at each point:
g"(0) = 2
g"(1) = 0
g"(-1) = 0
There is a local minimum at x = 0.
9514 1404 393
Answer:
(x, y) = (2, 1)
Step-by-step explanation:
Use the second equation to write an expression for x:
x = 1 +y
Substitute that into the first equation:
(1 +y) +4y = 6
5y = 5 . . . . . . . . subtract 1, collect terms
y = 1 . . . . . . . divide by 5
x = 1 +1 = 2 . . . use the expression for x to find x from y
The solution is (x, y) = (2, 1).
90cm^3. First, determine the area of the right triangle face, A=1/2(b*h) - 1/2(4.5*5) = 11.25cm^2. This triangle is repeated over 8cm, so we multiply the 11.25cm^2 * 8cm = 90cm^3.
Answer:
2:4
Step-by-step explanation: Subtract 1 from total amount then find the number of girls I think sorry
