Step-by-step explanation:
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2 answers:
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so we know has roots equal to the cube roots of 1, not including
itself, which are
Any polynomial of the form is divisible by
if both
and
(this is the polynomial remainder theorem).
This means
But since is a root to
, it follows that
and since , we have
so that
From here, notice that if for some integer
, then
which is to say, is divisible by
for all
in the given range that are *not* multiples of 3, i.e. the integers
and
for
.
Since 2005 = 668*3 + 1, it follows that there are integers
such that
.
Finally, .
Answer:
<em>Correct Answer: D</em>
Step-by-step explanation:
<em>Geometric Sequence </em>
We can find each term of a geometric sequence if we have the general formula by replacing n for any integer number in the given domain. n must be an integer because it's the position where the term is located. For example, is the term located in position 2, so n cannot be irrational or decimal. The sequence provided is
The variable n starts from 0 and has no limit, so the domain is a set of integers