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3 years ago

Solve the system of linear equations by substitution. x + 4y = 6 x - y = 1

Mathematics

1 answer:

bulgar [2K]3 years ago

6 0

9514 1404 393

Answer:

(x, y) = (2, 1)

Step-by-step explanation:

Use the second equation to write an expression for x:

x = 1 +y

Substitute that into the first equation:

(1 +y) +4y = 6

5y = 5 . . . . . . . . subtract 1, collect terms

y = 1 . . . . . . . divide by 5

x = 1 +1 = 2 . . . use the expression for x to find x from y

The solution is (x, y) = (2, 1).

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3 years ago

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How many of 26 gallons can go into quarts

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Anon25 [30]

Answer:

The one in the table on the left

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3 years ago

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Convert to the product of multiplication<br>a^2-b^2-4b-4

kirill [66]

$a^2-b^2-4b-4$ in form of multiplication is $(a-b)(a+b)-4(b+1)$ .

<u>Step-by-step explanation:</u>

We know that factors are the numbers that are being multiplied together . As 6532*7 = 45724 .Here 6532 & 7 are the factors and 45724 is product of the factors .

Here , we need to convert to the product of multiplication

a^2-b^2-4b-4 or , $a^2-b^2-4b-4$ :

⇒ $a^2-b^2-4b-4$

We know by identity that , $p^2-q^2 = (p-q)(p+q)$

⇒ $(a-b)(a+b)-4b-4$

Taking common term out as -4 :

⇒ $(a-b)(a+b)-4(b+1)$

Therefore , $a^2-b^2-4b-4$ in form of multiplication is $(a-b)(a+b)-4(b+1)$ .

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3 years ago