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chubhunter [2.5K]
2 years ago
15

For questions 15-17 use this triangle.

Mathematics
1 answer:
SIZIF [17.4K]2 years ago
8 0

Answer:

Part A)  The length of the hypotenuse of triangle ABC is

 

Part B) The length of the shorter leg of triangle ABC is

Part C) The length of the longer leg of triangle ABC is

Step-by-step explanation:

see the attached figure  to better understand the problem

Step 1

Find the length of the longer leg of triangle ABC  (side BC)

we know that  

In the right triangle DBC  

substitute the values and solve for BC

Step 2

Find the length of the shorter leg of triangle ABC  (side AC)

we know that  

In the right triangle ACD

substitute the values and solve for AC

Step 3

Find the length of the hypotenuse of triangle ABC (side AB)

Applying the Pythagoras theorem

we have

substitutes

 

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PLEASEEEEE HELPPPP MEEEEEEE BRAINLIEST TO THE FIRST ANSWER AND 30 POINTS
icang [17]

Answer:

CD ≠ EF

Step-by-step explanation:

Using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = C(- 2, 5) and (x₂, y₂ ) = D(- 1, 1)

CD = \sqrt{(-1+2)^2+(1-5)^2}

      = \sqrt{1^2+(-4)^2}

      = \sqrt{1+16} = \sqrt{17}

Repeat using (x₁, y₁ ) = E(- 4, - 3) and (x₂, y₂ ) = F(- 1, - 1)

EF = \sqrt{(- 1+4)^2+(-1+3)^2}

     = \sqrt{3^2+2^2}

     = \sqrt{9+4} = \sqrt{13}

Since \sqrt{17} ≈ \sqrt{13} , then CD and EF are not congruent

     

6 0
3 years ago
A fraction reduces to 36. If its denominator is 6x^5, what it's its numerator?
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