There are 30 students all together, and 4 of them are Freshman girls (Freshwomen ?). So the probability that one randomly chosen student is a Female Frosh is 4/30 = 2/15.
well, clearly the LCD from the denominators of 5 and 10 is just 10, thus

Find the area of all the separate figures and add them together
area of rectangle = length x width
11 x 3 = 33 ft
area of square = a^2
3^2 = 9ft
area of triangle = base x height over 2
11 x 3 = 33
33 over 2 = 16.5 ft
33 + 9 + 16.5 = 58.5 ft ^ 2
Answer:
3/2
Step-by-step explanation:
Let it be
C (5;4) , A (2;1) ; B(7;6)
Suppose that C divide the line AB in ratio m/n from point A (AC is m, CB is n)
Use the formula xc=(m*xb+n*xa)/ (m+n)
5=(m*7+2n)/(m+n)
5m+5n= 7m+2n
2m=3n
m/n=3/2
Given:
QSR is a right triangle.
QT = 10
TR = 4
To find:
The value of q.
Solution:
Hypotenuse of QSR = QT + TR
= 10 + 4
= 14
Geometric mean of similar right triangle formula:


Do cross multiplication.


Switch the sides.

Taking square root on both sides.

The value of q is
.