The sum of any two different odd numbers is divisible by 4.

Mathematics

2 answers:

bagirrra123 [75]1 year ago

4 0

Answer:

False

Step-by-step explanation:

counterexample: 3 + 7 = 10 . . . . not divisible by 4

The statement is FALSE.

An odd number can be represented by ...

2n+1 . . . . where n is any integer

Then a different odd number can be represented by ...

2m +1 . . . . where m is any integer

The sum of these numbers will be ...

(2n +1) +(2m +1) = 2n +2m +2 = 2(n +m +1)

This will be divisible by 2 for any integers m and n, but will only be divisible by 4 if exactly one of the integers m and n is odd.

jeyben [28]1 year ago

3 0

Step-by-step explanation:

are 1 and 3, then their sum is 4 which is divisible by 4.

are 3 and 5, their sum is 8 which is divisible by 4.

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Can you please help me guys

Korolek [52]

ANSWER

$y = 3 \cos(2x + 2) + 2$

or
$y= -3\cos(2x + 2) + 2$

Any of these two are correct

EXPLANATION

The general cosine function is

$y = a \cos(bx + c) + d$

where

$|a|=3$

$a=\pm3$

is the amplitude.

$\frac{2\pi}{b}= \pi$

is the period.

This implies that

$b=2$

$\frac{b}{c} = 1$

is the phase shift.

This implies that;

$c = 2$

$d = 2$

is the vertical shift.

The possible equations are:

$y = \pm \: 3 \cos(2x \pm2)+2$