This question is easy once you understand. So when adding, subtracting, multiplying, or dividing with whole numbers you turn it into a fraction. So 12 is going to become 12/1. 8 1/8 is a mixed number so we have to turn it into an incomplete fraction. Here is how you do it. Multiply the denominator by the who number. So 8 x 8 = 64. Then you add your product to the numerator, which will make it 65. Then after this you keep your denominator giving you 65/8. Now we have to find the common denominator by finding the LCM. So the LCM is 8. Next we divide the old denominator by the new denominator. So 1 goes into 8, 8 times. And next 8 x the numerator. so 8 x 12 = 96. We do the same to the other side. Now we have 96/8 - 65/8 = 31/8. Finally we make this a mixed number. So 31 divided by 8. So you should get 3 7/8.
I hope this helps! :)
40 wpm. Because 160/4=40.
I hope that helped!
2160
Explanation:
Use the equation (n-2)180
(14-2)180
(12)180
2160
The difference in elevation between the bottom of the canyon and the bird's nest is 947 1/2 feet
<h3>What is the difference in elevation between the bottom of the canyon and the bird's nest?</h3>
The given parameters are:
Nest = 71 4/5 feet above the seal level
Bottom of canyon = 875 7/10 below sea level
Below sea level means negative
So, we have:
Nest = 71 4/5 feet
Bottom of canyon = -875 7/10
The difference in elevation between the bottom of the canyon and the bird's nest is calculated as
Difference = |Nest - Bottom of canyon|
This gives
Difference = |71 4/5 - (-875 7/10)|
Evaluate the difference
Difference = |947 1/2|
Remove the absolute bracket
Difference = 947 1/2
Hence, the difference in elevation between the bottom of the canyon and the bird's nest is 947 1/2 feet
Read more about depth at:
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Answer: 2.093
Step-by-step explanation:
As per give , we have
Sample size : n= 20
Degree of freedom : df= n-1=19
Significance level : 
Since , the sample size is small (n<30) so we use t-test.
For confidence interval , we find two-tailed test value.
Using students's t-critical value table,
Critical t-value : 
Thus, the critical value for the 95% confidence interval = 2.093
