Ask question

Ask question

All categories

3 years ago

11

pLEASE HELP ME!!! this is due tonight! In a certain fraction, the denominator is 5 less than the number. If 3 is added to both t

he numerator and denominator, the resulting fraction is equal to 14/9. Find the original fraction.

1 answer:

jok3333 [9.3K]3 years ago

6 0

Answer: 11/6

Step-by-step explanation: Since 14 is already 5 more than 9, all you need to do is subtract 3 from each, then you get 11/6

You might be interested in

Solve the following equation for x. 5/8x +4 = 3/8x + 12

Rudik [331]

Answer:

X= 32

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

V square+6v-59=0<br> answer in one equation

Tema [17]

X= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$
a=1
b=6
c=-59
x= $\frac{-6+/- \sqrt{(6)-4(1)(-59)} }{2(1)}$
x= $-3+ 2\sqrt{17}$ and $-3- 2\sqrt{17}$

8 0

3 years ago

What is the distance around a triangle that has sides measuring 2 1/8, 3 1/2, and 2 1/2 feet?

Mashcka [7]

Perimeter = 2 1/8 + 3 1/2 + 2 1/2 = 7 (1 + 4 + 4)/8 = 7 9/8 = 8 1/8

3 0

3 years ago

27 players for 12 spots

labwork [276]

Answer: 27/12=2.25

Pretty simple:)

Step-by-step explanation:

7 0

3 years ago

I need help on a question

schepotkina [342]

Given the figure of a regular pyramid

The base of the pyramid is a hexagon with a side length = 6

The lateral area is 6 times the area of one of the side triangles

So, the side triangle has a base = 6

The height will be:

$\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}$

so, the lateral area =

$6\cdot\frac{1}{2}\cdot6\cdot\sqrt[]{63}=18\sqrt[]{63}$

3 0

1 year ago