How to solve the following system y=(1/2)x^2+2x-1 and 3x-y=1
1 answer:
Answer:
(0,-1),(2,5)
Step-by-step explanation:
3x-y=1
0.5+2x-1=y
Substitute the equation of y into the other equation
3x-(0.5+2x-1)=1
3x-0.5-2x+1=1
collect like terms
-0.5+x=0
Solve for x
x(-0.5x+1)=0
0=-0.5x+1
-1=-0.5x
x=2 x=0
Back substitute into the other original equation and solve for y
3(2)-y=1
6-y=1
y=5
(2,5)
3(0)-y=1
-1(-y)=-1(1)
y=-1
(0,-1)
You might be interested in
"Increasing" and "decreasing" are references to what the y-values do when the x-values increase.
Attached is a copy of all four tables, marked with whether the y-values increased or decreased on each step (and it also shows how much that increase or decrease was.
The only table that does this is the top right table in the attachment, which is your second table.
