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3 years ago

Explain how 49. 567 is done in fraction form

1 answer:

7 0

= 49567/1000

rite the decimal number as a fraction
(over 1)
49.567 = 49.567 / 1

Multiplying by 1 to eliminate 3 decimal places
we multiply top and bottom by 3 10's

Numerator (N)
N = 49.567 × 10 × 10 × 10 = 49567
Denominator (D)
D = 1 × 10 × 10 × 10 = 1000

N / D = 49567 / 1000

Simplifying our fraction

= 49567/1000

You might be interested in

Find the value of k for which the line y = kx + 6 is a tangent to the curve x^2 + y^2 – 10x + 8y = 84

guajiro [1.7K]

Answer:

k = 1/2

Step-by-step explanation:

input y = kx +6 into the equation of the curve x² + y² – 10x + 8y = 84

x² + (kx + 6)² - 10x + 8(kx + 6) = 84

expand:

x² + k²x² + 12kx + 36 - 10x + 8kx + 48 = 84

simplify by collecting like terms:

x² + k²x² + 20kx - 10x + 84 = 84

subtract 84 on both sides to bring it to the left:

x² + k²x² + 20kx - 10x + 84 - 84 = 0

x² + k²x² + 20kx - 10x = 0

factorise out x:

x²(1 + k²) + x(20k - 10) = 0

using the discriminant b² - 4ac where b is 20k - 10, a is 1 + k² and c is 0, substitute them in the formula b² - 4ac:

b² - 4ac

(20k - 10)² - 4(1 + k²)(0) = 0

the part highlighted in bold is gone because it's all multiplied by 0, so we are left with (20k - 10)² = 0

(20k - 10)² is the same as

(20k - 10)(20k - 10)

equate both to 0

20k - 10 = 0 and 20k - 10 = 0

add 10 on both sides

20k = 10 and 20k = 10

divide 20 on both sides

k = 10/20 and k = 10/20 which are both the same

10/20 is simplified to 1/2

k = 1/2

5 0

2 years ago

Tell whether the statement is true or false. { {4, 16, 24, 7, 37} = (37, 16, 7,42,4}

nikklg [1K]

Answer:

false

Step-by-step explanation:

i dont understand kinda

but if you add it,

88<106

so false

8 0

3 years ago

A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as

mamaluj [8]

Answer:

The farmer have at first 202 chickens.

Step-by-step explanation:

Given:

A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as ducks left.

Now, to find the chickens farmer have at first.

Let the chickens be $x.$

And, the ducks be $y.$

As, the farmer had twice as many chickens as ducks on his farm.

So, $x=2y$ ......(1)

As, given the farmer after selling 166 chickens and ducks, he had half as many chickens as ducks left.

According to question:

$x-166=(y-29)\times \frac{1}{2}$

$x-166=\frac{y-29}{2}$

Substituting the value of $x$ from equation (1) we get:

$2y-166=\frac{y-29}{2}$

By cross multiplying we get:

$4y-332=y-29$

Adding both sides 332 we get:

$4y=y+303$

Subtracting both sides by $y$ we get:

$3y=303$

Dividing both sides by 3 we get:

$y=101.$

Now, to get the number of chickens substituting the value of $y$ in equation (1):

$x=2y\\\\x=2\times 101\\\\x=202.$

Therefore, the farmer have at first 202 chickens.

7 0

3 years ago

What are the x-intercepts of the graphs of the function shown below y=x^2+4x-32?

stellarik [79]

They are x = 8 and x = -4

5 0

3 years ago

I'll give brainliest to whoever answers first CORRECTLY.

Semenov [28]

Answer:

I cant see the numbers clearly

Step-by-step explanation:

7 0

2 years ago