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REY [17]
2 years ago
12

Factorise fully 77x-33x^2

Mathematics
1 answer:
lesya [120]2 years ago
7 0

Answer:

11x(7 - 3x)

Step-by-step explanation:

77x - 33x² ← factor out 11x from each term

= 11x(7 - 3x)

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(4,2) graph the vertex
ipn [44]

Answer:

To plot (4,2) start at the origin (0,0) and move right 4 units and up 2 units (4,2)

3 0
3 years ago
Two mixed numbers that have a sum of 3
hram777 [196]
1 1/2 + 1 1/2 & 1 3/4 + 1 1/4
6 0
3 years ago
Choose the graphic representation of the quadratic function f(x) = x2 – 8x + 24.
larisa86 [58]

Refer the attached figure for the graphic representation of the given quadratic equation.

<u>Step-by-step explanation:</u>

Given expression:

    f(x)=x^{2}-8 x+24

To find:

  The graphic representation of the given quadratic function

For solution, plot the graph to the given quadratic equation.

The standard form of the equation is

  y=a x^{2}+b x+c

When comparing with given quadratic equation,

a = 1, b = - 8, c = 24

Axis of symmetry is x=\frac{-b}{2 a}

By applying the values, the axis of symmetry of given equation is

     x=\frac{-(-8)}{2(1)}=4

The vertex form of quadratic equation is f(x)=a(x-h)^{2}+k

Where, (h,k) are the vertex.

Convert the quadratic equation into vertex form.

By completing the square,

f(x)=x^{2}-8 x+24

f(x)=\left(x^{2}-2(4) x+4^{2}\right)-4^{2}+24

f(x)=(x-4)^{2}+8

On comparison,

(h , k) = (4 , 8)

Now, plot the equation with vertex (4,8) [refer attached figure].

4 0
3 years ago
Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that s
WINSTONCH [101]

Answer:  \bold{c=\dfrac{1+\sqrt{19}}{3}\approx1.8}

<u>Step-by-step explanation:</u>

There are 3 conditions that must be satisfied:

  1. f(x) is continuous on the given interval
  2. f(x) is differentiable
  3. f(a) = f(b)

If ALL of those conditions are satisfied, then there exists a value "c" such that c lies between a and b and f'(c) = 0.

f(x) = x³ - x² - 6x + 2     [0, 3]

1. There are no restrictions on x so the function is continuous \checkmark

2. f'(x) = 3x² - 2x - 6 so the function is differentiable \checkmark

3. f(0) =  0³ - 0² - 6(0) + 2 = 2

   f(3) =  3³ - 3² - 6(3) + 2  = 2

   f(0) = f(3) \checkmark

f'(x) = 3x² - 2x - 6 = 0

This is not factorable so you need to use the quadratic formula:

x=\dfrac{-(-2)\pm \sqrt{(-2)^2-4(3)(-6)}}{2(3)}\\\\\\.\quad =\dfrac{2\pm \sqrt{4+72}}{2(3)}\\\\\\.\quad =\dfrac{2\pm \sqrt{76}}{2(3)}\\\\\\.\quad =\dfrac{2\pm 2\sqrt{19}}{2(3)}\\\\\\.\quad =\dfrac{1\pm \sqrt{19}}{3}\\\\\\.\quad \approx\dfrac{1+4.4}{3}\quad and\quad \dfrac{1-4.4}{3}\\\\\\.\quad \approx1.8\qquad and\quad -1.1

Only one of these values (1.8) is between 0 and 3.

5 0
3 years ago
What is 3 x 9/100 as a fraction
Minchanka [31]
Becase 3x9=27 27/100 would be the awnser and is already in simplest form
7 0
3 years ago
Read 2 more answers
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