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Sonbull [250]
3 years ago
11

Quadratic linear and constant term of f(x)=(3x-6)(-4x+2)

Mathematics
1 answer:
navik [9.2K]3 years ago
8 0

Answer:

It is quadratic.

The constant term is:-12


Step-by-step explanation:

1. You can apply the Distributive Property of multiplication, as following:

f(x)=(3x-6)(-4x+2)\\f(x)=(3x)(-4x)+(3x)(2)+(-6)(-4x)+(-6)(2)\\f(x)=-12x^{2}+6x+24x-12\\f(x)=12x^{2}+30x-12

2. The function has the form:

f(x)=ax^{2}+bx+c

Therefore, it is a quadratic function, where c is the constant term.

3. Therefore, the constant term is -12


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