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torisob [31]
3 years ago
10

1,873 is roundes to the nearest thousand is

Mathematics
2 answers:
Talja [164]3 years ago
7 0
1,873 rounds to 2,000

5 or up u raise the score
Serjik [45]3 years ago
5 0
It would be 2,000. 1,873 rounded to the next number is 2,000, if the number was 1,499 you would round down but since the second number is higher than 5 you round up no matter what
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Select 2 strategies that we can use to add 115+497
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Answer:

  B. Add 115+500 then subtract 3

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Step-by-step explanation:

Any strategy that gives a sum of 612 will work. Strategy A gives a sum of 602, so is not useful.

The appropriate choices are B and C.

  B: 115 +497 = 115 +(500 -3) = (115 +500) -3

  C: 115 +497 = 115 +497 -3 +3 = (115 -3) +(497 +3) = 112 +500

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7 0
3 years ago
"4. A coffee manufacturer is interested in whether the mean daily consumption of regular-coffee drinkers is less than that of de
SSSSS [86.1K]

Answer:

With a 0.01 significance level and samples of 50 and 40 cofee drinkers, there is enough statistical evidence to state that the mean daily consumption of regular-coffee drinkers is less than that of decaffeinated-coffee drinkers.

The test is a one-tailed test.

Step-by-step explanation:

To solve this problem, we run a hypothesis test about the difference of population means.

$$Sample mean $\bar X: \bar X=4.35$\\Sample mean $\bar Y: \bar Y=5.84$\\Population variance $\sigma^2_X: \sigma^2_X=1.2^2$\\Population variance $\sigma^2_Y: \sigma^2_Y=1.36^2$\\Sample size $n_X=50$\\Sample size $n_Y=40$\\Significance level $\alpha=0.01$\\Z criticals values (for a 0.01 significance)\\(Left tail test) Z_{1-\alpha}=Z_{0.990}=-2.32635\\($Right tail test) Z_{\alpha}=Z_{0.010}=2.32636\\($Two-tailed test) $Z_{1-\alpha/2}=Z_{0.995}=-2.57583$ and $ Z_{\alpha/2}=Z_{0.005}=2.57583\\\\

The appropriate hypothesis system for this situation is:

H_0: \mu_X-\mu_Y=0\\H_a: \mu_X-\mu_Y  \leq 0\\\\

Difference of means in the null hypothesis is:

\mu_X - \mu_Y = M_0=0\\\\

$$The test statistic is$ Z=\frac{( \bar X-\bar Y)-M_0}{\sqrt{\frac{\sigma^2_X}{n_X}+\frac{\sigma^2_Y}{n_Y}}}\\$$The calculated statistic is Z_c=\frac{[(4.35-5.84)-0]}{\sqrt{\frac{1.20^2}{50}+\frac{1.36^2}{40}}}=-5.43926\\p-value = P(Z \leq Z_c)=0.0000\\\\

Since, the calculated statistic Z_c is less than critical Z_{1-\alpha}, the null hypothesis should be rejected. There is enough statistical evidence to state that the mean daily consumption of regular-coffee drinkers is less than that of decaffeinated-coffee drinkers.

7 0
3 years ago
Read 2 more answers
Help please. Brainleist goes to best answer
Bogdan [553]
Thank you very much Maz.
I really appreciate it :)
3 0
3 years ago
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