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2 years ago

Factor completely. -3x^2+9x+30

Mathematics

2 answers:

8090 [49]2 years ago

7 0

Answer:

− 3 ( x − 5 ) ( x + 2

Step-by-step explanation:

STatiana [176]2 years ago

6 0

Answer:

− 3 ( x − 5 ) ( x + 2 ) hope this helps

Step-by-step explanation:

You might be interested in

Zack watered his garden with 1 3/8

victus00 [196]

Answer:

The correct answer is that Zack used 2 7/8 gallons to water his garden on the fifth week.

Step-by-step explanation:

Let's find out the pattern Zack is using to water his garden, this way:

First week = 1 3/8 gallons of water

Second week = 1 3/4 gallons of water = 1 3/8 + 3/8 = 1 6/8 = 1 3/4

Third week = 2 1/8 gallons of water = 1 3/4 + 3/8 = 1 6/8 + 3/8 = 2 1/8

The constant of adding every week is 3/8 gallons, therefore,

Fourth week = 2 1/8 + 3/8 = 2 4/8 = 2 1/2 gallons of water

Fifth week = 2 1/2 + 3/8 = 2 4/8 + 3/8 = 2 7/8 gallons of water

The correct answer is that Zack used 2 7/8 gallons to water his garden on the fifth week.

3 0

3 years ago

16) (5x +2)(7x - 2) Ayoo can someone answer that man

algol [13]

(16) (12) (12) is the answer I think

5 0

2 years ago

Iris wants to buy a new pair of shoes that costs $30. She thinks that she can save $5 each week. How

Katena32 [7]

Answer:

The answer is 6 weeks

Step-by-step explanation:

To find the number of weeks she needs to save for we need to divide 30 by 5. 30÷5 = 6. Hope this helped!

5 0

2 years ago

Help me out please need this

olchik [2.2K]

the answer is ur guy

5 0

3 years ago

Find the area each sector. Do Not round. Part 1. NO LINKS!!

sladkih [1.3K]

Answer:

$\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2$

$\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta$

17) Given:

$\theta$ = 240°
r = 16 ft

$\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2$

19) Given:

$\theta=\dfrac{3 \pi}{2}$
r = 14 cm

$\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2$

21) Given:

$\theta=\dfrac{ \pi}{2}$
r = 10 mi

$\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2$

23) Given:

$\theta$ = 60°
r = 7 km

$\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2$

3 0

2 years ago