The age of Blain is 23 years old
<h3><u>Solution:</u></h3>
Let the age of Blain be "a" and age of Jillian be "b"
Given that Blain is two years older than three times Jillians age
So we can frame a equation as:
age of blain = 2 + 3(age of Jillian)
a = 2 + 3b ----- eqn 1
Also given that Jillian is also 16 years younger than Blain
Age of Jillain = Age of Blain - 16
b = a - 16 ---- eqn 2
Substitute eqn 2 in eqn 1
a = 2 + 3(a - 16)
a = 2 + 3a - 48
a - 3a = -46
-2a = -46
a = 23
Thus the age of Blain is 23 years old
Step-by-step explanation:
One gallon = 25 miles
8 gallon= 25×8 miles= 200 miles
∠ADC = 112°
∠ADC =6x + 7 + 12x - 3
Equate both:
6x + 7 + 12x - 3 = 112
Solve for x :
6x + 7 + 12x - 3 = 112
Combine like terms:
18x + 4= 112
Take away 4 from both sides:
18x = 108
Divide both sides by 18:
x = 6
Find ∠ADB:
6x + 7 = 6(6) + 7 = 43
Answer: ∠ADB = 43°
Answer:
x ---- y
1 ---- 3
4 ---- 12
6 ---- 18
Step-by-step explanation:
Given
Required
Create a table that represents this scenario
Because x represents time, x can not be negative. So, the domain of x is:
Assume 
Assume x = 4
Assume x = 6
Hence, the table is:
x ---- y
1 ---- 3
4 ---- 12
6 ---- 18
Answer:
20 pine trees
Step-by-step explanation:
No of pine trees today = 63
No of pine trees there = 43
So no of pine trees planted today= 63-43= 20
