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Setler79 [48]
3 years ago
11

Jaquay has a square garden with an area of 97 square feet. What is the length of each side of the garden?

Mathematics
1 answer:
mars1129 [50]3 years ago
8 0

Answer:

around 9.84 feet

Step-by-step explanation:

Because the area of a square is (length)(length), then the area is equal to (length)^2. So the square root of 97 is 9.84.

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The answer is c because S=Ph+2b
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What's the round tens of 14,249?
grin007 [14]
Rounding a number means to change its value slightly so it is not as exact as the original number. Numbers are rounded to a certain place value - tens, hundreds, thousands. etc..

Numbers are rounded to make it easier to do various math processes such as estimating costs in one's head or dividing larger numbers.

RULE: To round a two digit number or higher number to the nearest tens place:

If the number in the ones place of a two digit number is less than five, round the number down to the nearest tens place. If the number in the ones place is greater than five, round it up to the nearest tens plac.


Example 1: Round 23 to the nearest tens place

The number 3 in the ones place is less than five. Therefore the number 23 is rounded down to 20.
23 rounded to the nearest tens place is 20.


Example 2: Round 28 to the nearest tens place.

The number 8 in the ones place is greater than five. Therefore the number 28 is rounded up to 30.
28 rounded to the nearest tens place is 30.


Example 3: Round 94 to the nearest tens place.

The number 4 in ones place is less than five. Therefore the number 94 is rounded down to 90.
94 rounded to the nearest tens place is 90.


Example 4: Round the number 97 to the nearest tens place.

This one is tricky. The number 7 in the ones place is greater than five. Therefore the number 97 is rounded up to 100.
97 rounded to the nearest tens place is 100.
4 0
3 years ago
Read 2 more answers
Help!<br><br> Factor the expressions. <br> x2 + 62x + 120 =
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(X+60)(x+2) is the answer
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Solve the inequality.<br><br> 2(4 + 2x) ≥ 5x + 5?<br><br> x ≤ ?
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2(4+2x)≥5x+5
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3 years ago
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Draw the image of the following segment after a dilation centered at the origin with a scale factor of 2/3
Irina18 [472]

Answer:

Step-by-step explanation:

Let the ends of the given segment are A and B.

Coordinates of A → (8, 6)

Coordinates of B → (12, 12)

If a point (x, y) is dilated by a scale factor 'k' about the origin, rule to be followed,

(x, y) → (kx, ky)

If k = \frac{2}{3}

(x, y) → (\frac{2}{3}x, \frac{2}{3}y)

By this rule coordinates of the image points of A and B will be,

A(8, 6) → A'(\frac{2\times 8}{3},\frac{2\times 6}{3})

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B(12, 12) → B'(\frac{12\times 2}{3}, \frac{12\times 2}{3})

             → B'(8, 8)

Now we can get the image of segment AB after dilation by a scale factor of \frac{2}{3}.

5 0
3 years ago
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