No it does not, if you’re trying to solve for x you have to do PEMDAS
Answer:
0.2857
Step-by-step explanation:
Given that a company introduced a much smaller variant of its tablet, known as the tablet junior.
The weight was less than 11 oz. i.e. 50% lighter than std.
Let X be the battery life of the tablet junior
Then X is U(8.5,12)
Mean of X =10.25 hrs
the probability that the battery life for a tablet junior will be 9.5 hours or less
=
Answer:
Step-by-step explanation:
find LCM of the denominators= 77
so 66/77 - 63/77
3/77
hope this help you pls mark me as brainliest
working for division is on this question is
6/7 divide 9/11
so 6/7 *11/9
66/63 and then you can find its standard form and it cannot be do not
Answer:
4.75% probability that the battery will last more than 9 hours before running out of power
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that the battery will last more than 9 hours before running out of power g
This is 1 subtracted by the pvalue of Z when X = 9. So



has a pvalue of 0.9525
1 - 0.9525 = 0.0475
4.75% probability that the battery will last more than 9 hours before running out of power
1. Similar: all angles are equivalent.
2. Similar: 2 angles and 1 side are equivalent.
3. Not enough information.
4. Not enough information.
5. Not enough information.
6. False.
7. True.
8. True.
9. True.
10. False.