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quester [9]
2 years ago
7

6. h(x) = 10x – 4, find h(0.5)

Mathematics
2 answers:
STatiana [176]2 years ago
8 0

Answer:

h(0.5) = 1

Step-by-step explanation:

given  h(x) = 10x – 4

to find h(0.5), replace x with 0.5

h(0.5) = 10(0.5) – 4

h(0.5) = 1

e-lub [12.9K]2 years ago
6 0

Answer:

see below

Step-by-step explanation:

x=0.5. by substitution we get 10(0.5)-4=5-4=1

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The denominator of a fraction is greater than the numerator by 8. If the numerator is increased by 17 and denominator is decreas
MA_775_DIABLO [31]

Answer:\frac{13}{21}

Step-by-step explanation:

2( N+ 17) = 3 (N +7)

2N+ 34= ·3N+ 21

N= 13

D= N+8 = 13+8 = 21

Fraction is \frac{13}{21}

When Im using N is equal to numerator and D for denominator, in order to get the fraction we substitute and the results combine in the fraction like this  \frac{N}{D}

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1 year ago
A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of
Ivenika [448]

The equation for the height of the rocket at time t given

h= -16t^2+192t

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

h= -16t^2+192t

560 = -16t^2+192t

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

560 = -16(t^2 - 12t)

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

560/-16 = -16(t^2-12t)/-16

-35 = t^2 -12t

Now we will move -35 to the righ side by adding 35 to both sides.

-35+35 = t^2-12t+35

0 = t^2 -12t+35

t^2-12t+35 = 0

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

t^2-12t+35 =0

(t-5)(t-7) =0

So by using zero product property we will get

t-5 =0

t-5+5 = 0+5

t=5

Also t-7 =0

t-7+7 = 0+7

t=7

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

h= -16t^2+192t

0= -16t^2 + 192 t

0 = -16(t^2-12t)

-16(t^2-12t) = 0

We will move -16 to the other side by dividing it to both sides.

-16(t^2-12t)/-16 = 0/-16

t^2-12t = 0

We will take out the common factor t from the left side. By taking out t we will get,

t(t-12) = 0

We will use zero product property now. By using that we will get,

t = 0

ans also t-12 = 0

t-12+12 = 0+12

t = 12

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

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Answer:

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Step-by-step explanation:

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