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d1i1m1o1n [39]
3 years ago
12

I don't understand on how to get the answer for

Mathematics
1 answer:
yaroslaw [1]3 years ago
4 0

1/2 + 1/4 =

= 2/4 + 1/4

= 3/4

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Solve the equation and check the solution.
weqwewe [10]

Answer:

C

Step-by-step explanation:

You can write the equation like this:

A - 2.5 = 1.5

If you reverse the equation, it looks like this:

1.5 - 2.5 = A

1.5 - 2.5 = 4

A = 4

3 0
2 years ago
Read 2 more answers
HELP ME NOW ASAP PLEASE
sergejj [24]

Answer:

D. There are points on the graph with the same x-coordinate but different y-coordinate.

Step-by-step explanation:

A relation is a function if and only if each element of the range, corresponding with y-axis, is associated with only one element of the domain, corresponding with x-axis. In this case, the graphed relation is not a function, since for all element of the domain, except 0, are related to two distinct elements of the range.

Hence, correct answer is D.

6 0
2 years ago
Pick the description of a geometric object that best matches the real-world object:<br><br> tent
Elodia [21]

Answer:

Triangular Prism

Step-by-step explanation:

We are given the object 'Tent' and are required to find a 3D object resembling it.

Since, the object represents a tent. So, it must have two similar and parallel bases with parallelograms as sides.

Therefore, we get that the 3D object that resembles a tent is a 'Triangular Prism'.

A triangular prism has two similar triangular bases and three rectangular sides as shown in the figure below.

Hence, 'Triangular Prism' is the answer.

5 0
3 years ago
20 points to anyone who can answer number 3!!!!!
sp2606 [1]
My bad I didn't even read the directions haha, It is an 8 sided octogon and the sides are Irregular 
3 0
3 years ago
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Select the correct answer. Which expression is equivalent to 8x^2^3 sqrt 375x + 2^3 sqrt 3x^7, if x=0?
natima [27]

Answer:

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}

Step-by-step explanation:

The question is poorly formatted. The original question is:

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7

We have:

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7

Open bracket

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^{3* \frac{2}{3}}) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

Express 8 as 2^3

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^{3* \frac{2}{3}} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^2 *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

Express 2^3 as 8

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{75x^3} + 8\sqrt{ 3x^7}

Expand each exponent

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2 *3x} + 8\sqrt{ 3x * x^6}

Split

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2} *\sqrt{3x} + 8\sqrt{3x} * \sqrt{x^6}

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =4x^2 *5x *\sqrt{3x} + 8\sqrt{3x} * x^3

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =20x^3\sqrt{3x} + 8x^3\sqrt{3x}

Factorize

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}

4 0
3 years ago
Read 2 more answers
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