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CaHeK987 [17]
2 years ago
8

Solve for x.

Mathematics
1 answer:
TiliK225 [7]2 years ago
5 0

Answer:

x=47

Step-by-step explanation:

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HELPPPP ASAPPP!!! PLSSSSS I NEED HELPPP
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Answer:

Question 1= 10 and question 2=162

Step-by-step explanation:

use pemdas and multiply and add and stuff

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3 years ago
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4) In an isosceles trapezium , if one of the base angle is 65 degrees , then the other angles are ______
blagie [28]

Answer:

The other angles of the isosceles triangle are 65° and 50°

Step-by-step explanation:

By definition, the base angles of an isosceles triangle are equal, therefore, we have;

Where one of the base angles = 65°, the other base angle = 65°

To find the third angle, we proceed as follows

Let the third angle = ∠3

Let the two base angles = ∠1, and ∠2 such that ∠1 = ∠2 = 65°

Where ∠1 = 65° is the known base angle

By the sum of the interior angles of a triangle theorem, we have;

∠3 + ∠1 + ∠2 = 180°

∴ ∠3 + 65 ° + 65° = 180°

∠3 = 180° - (65 ° + 65°) = 180° - 130° = 50° By angle subtraction postulate

∴  The third angle = ∠3 = 50°

The other angles of the isosceles triangle are ∠2 = 65° and ∠3 = 50°.

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3 years ago
Simplify the complex fraction<br><br><br> 2/1/2 / 5/8
Tatiana [17]
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The size of a television screen is given as 95 cm, correct to the nearest 5 cm.
erica [24]

Answer:

The upper bound is 97.5 cm

Step-by-step explanation:

The upper bound is given as the value that is larger than or equal to all values in a data set, for example, in the data set, {3, 6, 16, 23, 25}, an upper bound  is 25, however, where the accuracy of the data is given, the upper bound can be found by the following relation

Where the number is given to the nearest 100, add and subtract  half of hundred to obtain the upper bound and lower bound respectively

For the question, given that the size of the television is given as 95 cm, correct to the nearest 5 cm, we add add half of 5 cm to get the upper bound as follows;

Upper bound = 95 cm + 5/2 cm = 97.5 cm

The upper bound = 97.5 cm.

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How to write 325,809 in expanded form
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