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Katen [24]
2 years ago
13

Once the prompt in image is read answer choices are:A. -0.9B. -0.4C. 0.4D. 0.9​

Mathematics
1 answer:
kozerog [31]2 years ago
5 0
I don’t understand what exactly you want
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Can anyone help me with this one
aleksandrvk [35]
50 hours!

825 (paycheck left over) + 25 (the shirt that was subtracted because he bought it) = $850 total
850 (total amount this week) / 17 (the amount he makes per hour) = 50 (total amount of hours worked this week)
8 0
2 years ago
Events M and N are independent events. In this scenario, if P(M) = 0.46 and P(M and N) = 0.138, then P(N) = .
Oksi-84 [34.3K]

Answer:

P(N)=0.3

Step-by-step explanation:

Given: P(M)= 0.46, P(M and N)=0.138

Using P(M) ×P(N)= P(M and N)

⇒0.46×P(N)= 0.138

⇒P(N)= \frac{0.138}{0.46}

⇒P(N)=0.3

7 0
3 years ago
Read 2 more answers
Equation of a line, in general form, that is perpendicular to 2x-3y + 7 = 0 and passes through the point (-3/4, 1)
TEA [102]

Answer:

  12x +8y +1 = 0

Step-by-step explanation:

You can write the equation by swapping the x- and y-coefficients and negating one of them. Then compute the constant that makes the line go through the given point. You can do that like this:

  3(x-(-3/4)) +2(y -1) = 0

  3x +9/4 +2y -2 = 0 . . . . eliminate parentheses

  3x +2y +1/4 = 0 . . . . . . . simplify

To eliminate the fraction, multiply by 4:

  12x +8y +1 = 0

_____

<em>Comment on the equation</em>

The line ax+by=0 passes through the origin. Replacing x and y with x-h and y-k, respectively, makes the line pass through the point (h, k). That's what we did above to make the line pass through the given point.

The business of swapping coefficients and negating one causes the slope of the new line to be the negative reciprocal of the slope of the original line. That is what makes the new line perpendicular to the original.

4 0
3 years ago
Simplify the given equation in the attached picture:<br><br>\sqrt{29-\sqrt{5}}
Vilka [71]

Answer: 2√5 - 3

Step-by-step explanation:

$$Simplify the following:$\sqrt{29-12 \sqrt{5}}$$$\begin{aligned}&29-12 \sqrt{5}=9-12 \sqrt{5}+20=9-12 \sqrt{5}+4(\sqrt{5})^{2}=(2 \sqrt{5}-3)^{2}: \\&\sqrt{\left((2 \sqrt{5}-3)^{2}\right)}\end{aligned}$$Cancel exponents. $\sqrt{(2 \sqrt{5}-3)^{2}}=2 \sqrt{5}-3$ :\\Answer:$$2 \sqrt{5}-3$$

3 0
2 years ago
In response to the increasing weight of airline passengers, the Federal Aviation Administration in 2003 told airlines to assume
schepotkina [342]

Answer: 0.0016

Step-by-step explanation:

Given the following :

Population mean(m) = 196

Population Standard deviation (sd) = 32

Number of sample (n) = 18

Sample mean (x) = Total weight of sample / number of samples = 3928 / 18 = 218.2

Obtaining the test statistic (z) :

Z = [(x - m) / (sd/√n)]

Z = [(218.2 - 196) / (32/√18)]

Z = [(22.2 / 7.5424723)]

Z = 2.943

Hence,

P(Z > 2.94) = 1 - P(Z < 2.94)

= 1 - 0.9984

= 0.0016

4 0
3 years ago
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