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2 years ago

Please help :) Is the relationship shown by the data linear? If so model the data with an equation.

Mathematics

1 answer:

MrRissso [65]2 years ago

5 0

Answer:

y-5=5/4(x-1)

Step-by-step explanation:

the slope is 1.25

m=y2-y1/x2-x1=10-5/5-1=5/4=1.25

y-5=(5)/(4)(x-1)=

y=(5)/(4)x+(15)/(4) this one is linear

it is a linear function and the

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Solve A= P+Prt for r. Assume all variables represent positive values.

Fed [463]

A = P + Prt
A = P/P + Prt/P
A = P(1 + rt)
A/P = P(1 + rt)/P
A/P = 1 + rt
A/P - 1 = 1 - 1 + rt
A/P - 1 = rt
(A/P - 1)/t = rt/t
(A/P - 1)/t = r

Thus r = (A/P - 1)/t.

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ziro4ka [17]

Answer:

Step-by-step explanation:

1) Mark two points on the line in the graph.

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Run -----> difference in x-coordinates (x2 - x1)

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1.If slope = 0, then the line is parallel to x-axis.

2. If slope is undefined, then the line is parallel to y-axis.

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Tim drives at an average of 80km

guapka [62]

Answer:

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Step-by-step explanation:

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