Answer:
=5x2+5x
Step-by-step explanation:
Let's simplify step-by-step.
3x+3x2+2x2+2x
The given equation of the ellipse is x^2
+ y^2 = 2 x + 2 y
At tangent line, the point is horizontal with the x-axis
therefore slope = dy / dx = 0
<span>So we have to take the 1st derivative of the equation
then equate dy / dx to zero.</span>
x^2 + y^2 = 2 x + 2 y
x^2 – 2 x = 2 y – y^2
(2x – 2) dx = (2 – 2y) dy
(2x – 2) / (2 – 2y) = 0
2x – 2 = 0
x = 1
To find for y, we go back to the original equation then substitute
the value of x.
x^2 + y^2 = 2 x + 2 y
1^2 + y^2 = 2 * 1 + 2 y
y^2 – 2y + 1 – 2 = 0
y^2 – 2y – 1 = 0
Finding the roots using the quadratic formula:
y = [-(- 2) ± sqrt ( (-2)^2 – 4*1*-1)] / 2*1
y = 1 ± 2.828
y = -1.828 , 3.828
<span>Therefore the tangents are parallel to the x-axis at points (1, -1.828)
and (1, 3.828).</span>
The given equation is: 
To find the line perpendicular to it, we interchange coefficients and switch the signs of one coefficient.
The equation to a line perpendicular to it is:
$ 2y-x=c$
where, $c$ is some constant we have determine using the condition given.
It passes through $(2,-1)$
Put the point in our equation:
$2(-1)-(2)=c$
$c=-2-2$
$c=-4$
The final equation is:
$\boxed{ 2y-x=-4}$
Answer:
5
Step-by-step explanation:
This is a right triangle, but note that you only know the measurement of one angle, which is 90 degrees.
Use the following formula to solve:
a² + b² = c²
In which:
a & b = shorter sides
c = hypotenuse
Plug in the corresponding numbers to the corresponding variables:
(3)² + (4)² = ?²
Solve. Remember to follow PEMDAS. First, solve the exponents, then add:
(3)² = (3 * 3) = (9)
(4)² = (4 * 4) = (16)
9 + 16 = ?²
25 = ?²
Isolate "?". Root both sides:
√(25) = √(?²)
? = √25 = √(5 * 5) = 5
Your missing side's measurement is 5.
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Step-by-step explanation:
I don't get the question a bit but I hope this makes sense
:)
