The method I'll be presenting is the old traditional way, hehe.
33 x 76 ——
1) 3 x 6 is 18.
1 33 x 76 —— 8
2) Again, 3 x 6 is 18, adding 1 (since you carry the 1 in 18 over) is 19.
1 33 x 76 —— 198
3) 3 x 7 is 21.
2 1 33 x 76 —— 198 1
4) Once again, 3 x 7 is 21, plus 1 is 23.
2 1 33 x 76 —— 198 231 ———
4) Now we add 198 + 231.
33 x 76 —— 1 198 (PS. carry the 231 one in 1+9) ——— 2508
5) Now we round, in this case we shall round to the nearest thousand since it makes sense too.
2,508 ^ Take a look at the thousands place, which is two.
2,508 ^ To the right of 2 is 5. Any number to the right between 5-9 you add one to the place value and zap the rest of the numbers to the right to 0. So...
